Relationship between chemical equilibrium and rate equilibrium

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SUMMARY

The discussion clarifies that the equilibrium constant (K) is independent of the initial amounts of reactants and products in a chemical reaction. It emphasizes that while K is related to the ratio of the forward (kf) and reverse (kr) rate constants, the individual rate constants do not influence the equilibrium constant directly. The relationship between K and the rate constants is established through the equation K = kf/kr, highlighting that changes in one rate constant necessitate changes in the other.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with reaction kinetics
  • Knowledge of equilibrium constant calculations
  • Basic grasp of rate constants (kf and kr)
NEXT STEPS
  • Study the derivation of the equilibrium constant from rate laws
  • Explore the concept of dynamic equilibrium in chemical reactions
  • Investigate the effects of temperature on equilibrium constants
  • Learn about Le Chatelier's principle and its application to equilibrium shifts
USEFUL FOR

Chemistry students, educators, and professionals in chemical engineering or research who seek to deepen their understanding of the relationship between chemical equilibrium and reaction rates.

r12214001
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Homework Statement
equilibrium
Relevant Equations
equilibrium
Q: Is it true that the value of K depends on the amounts of reactants and products mixed together initially? Explain.

A:NO, Equilibrium and rates of reaction (kinetics) are independent of each other. A reaction with a large equilibrium constant value may be a fast reaction or a slow reaction. The same is true for a reaction with a small equilibrium constant value.

why the solution manual state that independent of each other?
In my opinion that rate constant of K(forward)/K(reverse)=K(equilibrium constant). Regarding this equation, we can get that K(equilibrium constant) is related to rate constant of K .it is not independent !
 
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You haven't quoted the question or the solution manual very completely but pretty surely you have not answered the question which asks nothing about rates.
 
r12214001 said:
In my opinion that rate constant of K(forward)/K(reverse)=K(equilibrium constant). Regarding this equation, we can get that K(equilibrium constant) is related to rate constant of K .it is not independent !

It depends on what you mean by "independent". In the kinetic approach to equilibrium you can say K depends on the kf/kr ratio, but it is not the same thing as each k separately. Especially taking into account fact you can't change one of ks without changing the other at the same time.
 

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