Consider a solid disk of mass m and radius R rolling along a horizontal surface with the center of the disk moving horizontally with a speed v. The total kinetic energy of the disk is a combination of translational kinetic energy , KEt and rotational kinetic energy, KEr. Find the ration KEt/KEr
The Attempt at a Solution
I basically broke down the equations into their simplest forms to try to find the relationship. So
E = 1/2mv^2 + 1/2IW^2
E = 1/2mv^2 + 1/2 (1/2mR^2)w^2
E = 1/2mv^2 + 1/4mR^2 * W^2
I am really not sure how to how about solving this problem. I know I could make up some imaginary numbers for the variables and just guess and check for the relationship but I would prefer to solve this algebraically. The correct answer is 2.