Relationship of velocity of an electron/velocity of proton to mass ratio

Click For Summary
SUMMARY

The discussion focuses on deriving the ratio of the velocities of an electron and a proton when both are accelerated through the same electric potential difference. The key equations utilized are derived from the conservation of energy, specifically the relationship \( v^2 = -2q\Delta V \cdot \frac{1}{m} \). The final expressions for the velocities are \( v_e^2 = -2q_e\Delta V \cdot \frac{1}{m_e} \) for the electron and \( v_p^2 = -2q_p\Delta V \cdot \frac{1}{m_p} \). The ratio \( \frac{v_e}{v_p} \) can be expressed in terms of the charge and mass of the electron and proton.

PREREQUISITES
  • Understanding of electric potential difference and its effects on charged particles
  • Familiarity with the conservation of energy principle in physics
  • Knowledge of basic kinematics and equations of motion
  • Concept of mass-energy equivalence and its implications for particle velocities
NEXT STEPS
  • Study the derivation of the kinetic energy formula \( KE = \frac{1}{2}mv^2 \)
  • Learn about the behavior of charged particles in electric fields
  • Explore the implications of relativistic effects on particle velocities at high speeds
  • Investigate the differences in mass and charge between electrons and protons
USEFUL FOR

Students and educators in physics, particularly those studying electromagnetism and particle dynamics, as well as anyone interested in the fundamental principles governing charged particle motion.

sheri1987
Messages
47
Reaction score
0
Relationship of velocity of an electron/velocity of proton to...mass ratio

Homework Statement



An electron and a proton, starting from rest, are accelerated through an electric potential difference of the same magnitude. In the process, the electron acquires a speed ve, while the proton acquires a speed vp.


--------------------------------------------------------------------------------

(d) What is the algebraic expression for the ratio ve/vp of the speed of the electron to that of the proton? Express your answer in terms of the mass me of the electron and the mass mp of the proton. (Answer using m_e for me and m_p for mp.)

Homework Equations



SO I need to write an equation relating Velocity of electron/ velocity of proton...I understand that much...but I am unsure where to start.

I think I need the equation 1/2mv^2 = -q (charge)deltaV(voltage)


The Attempt at a Solution



by using the equation above I solved and got sqrt(2qdeltaV/m) ...I am not sure where to go next...? Can anyone help me out?
 
Physics news on Phys.org
sheri1987 said:
I think I need the equation 1/2mv^2 = -q (charge)deltaV(voltage)

Yes, that's what you want to use.

by using the equation above I solved and got sqrt(2qdeltaV/m) ...I am not sure where to go next...? Can anyone help me out?

Actually, you should get sqrt(-2qdeltaV/m). Then if q<0 (like it is for an electron) then deltaV>0 and the radicand is positive. And if q>0 (like it is for the proton) then deltaV<0, and again the radicand is positive. Just find expressions for the speeds of the proton and the electron, and take their ratio and you'll have it.
 
sheri1987 said:
by using the equation above I solved and got sqrt(2qdeltaV/m) ...I am not sure where to go next...? Can anyone help me out?
So you have used conservation of energy to almost correctly [note the sign correction] solved for the velocity of a generic particle of charge q and mass m (traveling at non-relativistic speeds). Let me write your equation out in a form that may be easier to work with;

v^2 = -2q\Delta V \cdot \frac{1}{m}

So now you want that ratio v_e/v_p. So you can now write two equations;

v_e^2 = -2q_e\Delta V \cdot \frac{1}{m_e}

v_p^2 = -2q_p\Delta V \cdot \frac{1}{m_p}

Can you take the next step?

Edit: Tom beat me to it!
 
Last edited:

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K