1. The problem statement, all variables and given/known data A 10 gram silver sphere is charged until it acquired a charge of -1.2 coulomb. Find ratio of number of electron to number of proton in spere. Given that silver atomic weight and atomic number 107.87 and 47 2. Relevant equations 3. The attempt at a solution first i calculated extra electron = -1.2/1.60217657 × 10-19 Since number of proton = number of elelectron before acquired charge . Number of new electron = 47 +1.2/1.60217657 × 10-19.. and then dividing it by 47 . To get the ratio . My question is that correct what i did . And if yes we he mentioned mass of silver and atomic weight.