Relative Motion Question (PHYSICS 20)

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SUMMARY

The discussion focuses on calculating the resultant velocity of a swimmer crossing a river. The swimmer moves at 3.5 m/s at an angle of 30° North of East, while the river flows southward at 4.0 m/s. The resultant velocity is determined to be 3.8 m/s at an angle of 37° South of East. The calculations involve breaking down the swimmer's velocity into components and applying trigonometric principles.

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  • Understanding of vector addition in physics
  • Knowledge of trigonometric functions (SOH CAH TOA)
  • Familiarity with velocity and motion concepts
  • Ability to perform basic arithmetic operations with vectors
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Homework Statement



You swim from the west to the eastern shore across a 30m wide section of the bow river at 3.5m/s @ 30° N of E. If the river flows southward at 4.0m/s, determine your resultant velocity/


Homework Equations



- Trig (SOH CAH TOA)


The Attempt at a Solution



So first I drew the vector 3.5 m/s @ 30° N of E and found y ( 1.75 m/s [N] ) and the x
( 3.031 m/s [E] ). From the question, 4.0 m/s - 1.72 m/s [N] = 2.25 m/s . Therefore, the new triangle would have x= 3.031 m/s and y= 2.25 m/s with hyp = 3.77m/s with the angle of 36.6

ANS = 3.8 m/s @ 37° S of E (??)
 
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whitsstar said:

Homework Statement



You swim from the west to the eastern shore across a 30m wide section of the bow river at 3.5m/s @ 30° N of E. If the river flows southward at 4.0m/s, determine your resultant velocity/


Homework Equations



- Trig (SOH CAH TOA)


The Attempt at a Solution



So first I drew the vector 3.5 m/s @ 30° N of E and found y ( 1.75 m/s [N] ) and the x
( 3.031 m/s [E] ). From the question, 4.0 m/s - 1.72 m/s [N] = 2.25 m/s . Therefore, the new triangle would have x= 3.031 m/s and y= 2.25 m/s with hyp = 3.77m/s with the angle of 36.6

ANS = 3.8 m/s @ 37° S of E (??)

Welcome to PF.

Your solution is correct :approve:
 

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