I'm getting myself confused here. If my relativistic Lagrangian for a particle in a central potentai is(adsbygoogle = window.adsbygoogle || []).push({});

[tex]L = \frac{-m_0 c^2}{\gamma} - V(r) [/tex]

should

[tex] \frac{d L}{d \dot{\theta}} [/tex]

not give me the angular momentum (which is conserved)? Instead I get

[tex] \frac{d L}{d \dot{\theta}} = -4 m v r^2 \dot{\theta}\gamma [/tex]

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# Relativistic angular momentum and cyclic coordinates

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