Relativistic centripetal force is a byproduct of time

In summary, the conversation discusses the concept of objects moving in circular motion and the presence of forces such as centrifugal and centripetal forces. It also delves into the role of time variation along the radial direction and how it affects acceleration. Finally, it touches on the fact that this acceleration can be explained by a potential in the framework of General Relativity.
  • #1
Somsak
7
0
From special relativity, we know that
t=t0/(1-v2/c2)1/2
For the object moves as a circle with radius r, the velocity v = w r
Therefore, time varying along radius r as
t=t0/(1-w2 r2/c2)1/2
In this case
ds2= dr2- c2 dt2 = dr2- c2 dt02 /(1-w2 r2/c2)
Since object will move in shortest path in space-time, Dif[ds2,dr] = 0,
and Dif[r,dr] = 1, the above equation will be
0 =2 dr - 2 w2 r dt02 /(1-w2 r2/c2)2
That means the object will move dr due to time varying along radius r as
dr = w2 r dt02 /(1-w2 r2/c2)2 = w2 r dt2 /(1-w2 r2/c2)
Or the object will move with accelleration as
dr/dt2 = w2 r /(1-w2 r2/c2)

This accelleration is look like acting by centrifugal force.
 
Last edited:
Physics news on Phys.org
  • #2
Somsak said:
object will move in shortest path in space-time

This is not correct. Objects that are in free fall move on the longest paths in spacetime, not the shortest. But the object you are considering is not in free fall.

Also, I'm not clear on what question you are asking.
 
  • #3
I try to proof that this accelerate due to time varying along r. No centrifugal force.
 
Last edited:
  • #4
Somsak said:
I try to proof that this accelerate due to time varying along r. No centripetal force.

Proper acceleration can't be explained by "time variation" (to the extent that even makes sense). Nonzero proper acceleration means a force is acting on the object; there's no way to transform away that force by changing coordinates.

Your math does not look correct in any case. First, as I pointed out before, you are assuming that the object travels on the "shortest path" in spacetime, whereas in fact its path is not extremal at all, since it is not in free fall. Second, you claim to be deriving an equation for ##dr / dt## that says it is nonzero; but you started out with the assumption that the object is moving in a circle with constant ##r##, i.e., ##r## does not change with time. So your analysis looks self-contradictory.
 
  • #5
Somsak said:
I try to proof that this accelerate due to time varying along r. No centripetal force.
I'm not sure what this means. This good Wiki article covers circular motion in Minkowski spacetime.

http://en.wikipedia.org/wiki/Born_coordinates

The general geodesic condition for circular motion is ##2g_{tt}r\omega^2=\partial_r g_{tt}## which in Minkowski spacetime has no solution. If ##g_{tt}## is from the Schwarzschild vacuum solution, then there is a solution which looks like a relativistic Keplers law.
 
Last edited:
  • #6
Somsak said:
I try to proof that this accelerate due to time varying along r. No centripetal force.
Are you perhaps talking about a circular orbit in the Schwarzschild spacetime? If not then I don't know of a way to get a circular path without a centripetal force.
 
  • #7
I suspect that if we identify "centripital force" with ##\Gamma^r{}_{tt}##, or possibly ##\Gamma^\hat{r}{}_{\hat{t}\hat{t}}##, using a rotating metric like
rotmetric.png

a detailed calculation would wind up show that the "force" (christoffel symbol) is proportional to ##\partial_r \sqrt{|g_{00}|}##, i.e. the partial derivative with respect to r of the "time dilation factor". Another way of saying this would be that I'd expect the force (christoffel symbols) to be proportional to the gradient of some "effective potential", a relativistic version of the effective potiential one uses to find the figure of the rotating Earth (by setting the effective potential equal to a constant). But I haven't worked out the details.
 
  • #8
pervect said:
I suspect that if we identify "centripital force" with ##\Gamma^r{}_{tt}##, or possibly ##\Gamma^\hat{r}{}_{\hat{t}\hat{t}}##, using a rotating metric like
View attachment 83655
a detailed calculation would wind up show that the "force" (christoffel symbol) is proportional to ##\partial_r \sqrt{|g_{00}|}##, i.e. the partial derivative with respect to r of the "time dilation factor". Another way of saying this would be that I'd expect the force (christoffel symbols) to be proportional to the gradient of some "effective potential", a relativistic version of the effective potiential one uses to find the figure of the rotating Earth (by setting the effective potential equal to a constant). But I haven't worked out the details.
I did the detailed calculation some ago and you are correct as the equation I cited above shows. (My ##g_{tt}## is a positive number which gets its sign from the signature)
 
  • #9
May I explain more by this example... A ball is in a slot on a disk. This slot is in the radial direction of the disk. When we spin the disk, the ball will be accelerated by centrifugal force. I think actually there is no centrifugal force, but this acceleration is due to time varying along r.
 
  • #10
Sorry that I have a little bit English confusion. Now I've changed from "centripetal force" to "centrifugal force".
 
  • #11
Somsak said:
May I explain more by this example... A ball is in a slot on a disk. This slot is in the radial direction of the disk. When we spin the disk, the ball will be accelerated by centrifugal force. I think actually there is no centrifugal force, but this acceleration is due to time varying along r.

I think you are saying that the centrifugal force can be explained by a potential.

This is what GR already shows. In holonomic coordinates the acceleration is a kinematic effect ( depending on velocity) but in the local frame calculation it becomes a velocity-dependent potential by the transformation of a Christoffel symbol to a Ricci rotation coefficient.

I've calculated the potential and I can show the working if you want to see it.
 
Last edited:
  • #12
Somsak said:
A ball is in a slot on a disk. This slot is in the radial direction of the disk. When we spin the disk, the ball will be accelerated by centrifugal force.

Ok, this is a different scenario from what it seemed like you were describing in the OP. Note that there are two "forces" that the ball is subjected to: one in the radial direction (the one you are talking about), and the other in the tangential direction (because the slot is pushing sideways on the ball).

Somsak said:
I think actually there is no centrifugal force, but this acceleration is due to time varying along r.

It's due to picking a non-inertial frame; "time varying" only applies in that frame. In an inertial frame in which the center of the disk is at rest, there is no "time varying", and also no centrifugal force; the only force acting on the ball is the tangential force of the slot pushing sideways on it.
 
  • #13
Mentz114 said:
I've calculated the potential and I can show the working if you want to see it.
Please show your work. Thank you.
 
  • #14
PeterDonis said:
Ok, this is a different scenario from what it seemed like you were describing in the OP. Note that there are two "forces" that the ball is subjected to: one in the radial direction (the one you are talking about), and the other in the tangential direction (because the slot is pushing sideways on the ball).
I think it's quite interesting how the force in the radial direction, centrifugal force, came from. Thereforce, I try to proof that actually no centrifugal force, but the acceleration is due to time varying along r.
 
  • #15
Somsak said:
Please show your work. Thank you.
OK I've attached a cut-down section of my notes. This is not an article although it has that format because I don't have a suitable Latex document template (!).
I've done my best to get everything right but I cannot be certain there aren't mistakes. Also I never finished section 4 because it looks like circular logic (pun).
 

Attachments

  • SRGRRotation.pdf
    221.6 KB · Views: 256
  • #16
Somsak said:
I think it's quite interesting how the force in the radial direction, centrifugal force, came from.

As I said before, it comes from using a non-inertial frame.

Somsak said:
I try to proof that actually no centrifugal force, but the acceleration is due to time varying along r.

All this "proof" shows is the consequences of using a non-inertial frame. If you use an inertial frame, the "time varying along r" disappears. But you can't change physics by changing frames.
 
  • Like
Likes nitsuj
  • #17
I think the following is vague enough to be true. I don't really have the inclination to work out all the details at the moment to say anything more specific, so take this whole post with a grain of salt, it's an idea that needs more development and testing. The idea is that there is some effective potential (velocity dependent in the case of a stationary metric, a scalar potential in the more familiar static metric case). The exact form of the effective potential depends on the coordinate choice, for instance if you have a non-rotating flat space metric, the effective potential is zero, but if you have a rotating flat metric, which is just a different choice of coordinates, the effective potential is not zero. The claim is basically that the gradient of the effective potential can be related to the "force" and the value of the potential itself can be related to time dilation. In the rotating case, the claim is that the value of the effective potential when the velocity-dependent part is zero gives the "centrifugal force". The velocity-dependent part would be related to the coriolis force, but I don't think anyone is exploring this aspect.

Anyway, since both "force" and time dilation can be derived in the static/stationary case from the effective potential, the claim is that there is a close relationship between the two. Interpreting this relation as "time dilation causes gravity" appears attractive, but is certainly not equivalent to Einstein's field equations. One difference that comes to mind is that Einstein's field equations predict non-Euclidean spatial geometries, this would not be a prediction of the "time dilation causes gravity" idea. However, this doesn't come about in the rotating case, it's more of a concern in the Schwarzschild case.

Experiment favors GR, of course, if one regard the two as competing theories by exploring their predictions. The non-zero value of the PPN parameter gamma pretty much rules out an Euclidean spatial geometry for the solar system metric, which means that spatial geometry of the solar system isn't Euclidean.
 
  • #18
pervect said:
...
The exact form of the effective potential depends on the coordinate choice, for instance if you have a non-rotating flat space metric, the effective potential is zero, but if you have a rotating flat metric, which is just a different choice of coordinates, the effective potential is not zero.
Having decided to look at circular motion in flat spacetime one is constrained to look at world lines of bodies moving in circles, like the Born and Langevin congruences. So I don't understand your point about anything I claim being dependent on choice of coordinates. For these congruences the acceleration is proper and all observers will agree about that.( I don't know if I am amongst those claiming)
The claim is basically that the gradient of the effective potential can be related to the "force" and the value of the potential itself can be related to time dilation. In the rotating case, the claim is that the value of the effective potential when the velocity-dependent part is zero gives the "centrifugal force". The velocity-dependent part would be related to the coriolis force, but I don't think anyone is exploring this aspect.
When writing the Hamiltonian of particle moving on a given worldline, the 'time-dilation' ##dt/d\tau## is treated as a potential. There is unusual about this.

What I claim is that the physical effects ( eg proper acceleration) which are put down to the velocity in the holonomic basis, must be moved into the potential sector in the local basis or be lost. And this is what happens, which is no surprise.

I think the OP noticed that ##\partial_r \dot{t}## for some worldline gives the correct acceleration and then used faulty logic to 'prove' this.

But by an amazing coincidence, this is actually what happens. In the local frame basis the kinematic effect has become a potential equal to ##\dot{t}##. And since the OP asked to see the working, I gave them both barrels.

I hope it had a salutory effect. But I suspect it has been a waste of time.

[edit]
I cut out some not relevant stuff and changed a few words in my doc.
 

Attachments

  • SRGRRotation.pdf
    211.5 KB · Views: 243
Last edited:
  • #19
I was thinking about this issue some more, and I came to the conclusion that we can relate the link between time dilation and force to the existence of a conserved energy. Specifically, the Komar energy in any static or stationary space-time - the rotating space-time being an example of the stationary case.

So, the rate of change of energy with distance is related to force, via the principle that energy = force*distance. But this "force" can and usually will be different from the proper acceleration that a local observer with constant coordinates measures. There is some discussion in Wald on this (see the disucssion on the force at infinity) in his discussion of energy in his book "General Relativity". This creates the link between energy and force.

At the risk of creating more confusion, I'll describe how we could measure the "force". If we had a masless string (a string that was pure tension in its rest frame), we would measure the "force" on a rotating object by the tension in the massless string at the center of rotation. The continuity equations and time dilation make the "force" we measure this way different than the "force" (tension) at the end of the string (the end attached to the rotating object). The two tensions will be different, only the later value would be equal to the reading of an accelerometer on the object multiplied by its mass. Hence the ambiguity in what we mean by "force".

The conservation of energy implies that there will be a constant and reciprocal red/blue shift between any pairs of points with constant coordinates via the usual arguments based on the principle of equivalence and "falling photons". These red/blue shifts are interpreted as time dilation, so we have the link from energy to time dilation.

Thus we can link both time-dilation and "force" to energy, explaining the observed relationship, which is not a coincedence, but necessary - as long as we meet the required conditions of a static or stationary space-time.
 
Last edited:
  • #20
pervect said:
I was thinking about this issue some more, and I came to the conclusion that we can relate the link between time dilation and force to the existence of a conserved energy. Specifically, the Komar energy in any static or stationary space-time - the rotating space-time being an example of the stationary case.

[snipped to save space and electrons]
..
Thus we can link both time-dilation and "force" to energy, explaining the observed relationship, which is not a coincedence, but necessary - as long as we meet the required conditions of a static or stationary space-time.

In as much as I understand the above I agree.

But I think one ought to concentrate on the local physics. If I spin a disk in my lab then I can analyse my results without giving any thought to boundaty conditions at infinity. If we analyse always in terms of proper time and restrict our conclusions to the spacetime region in which our ( Fermi-Walker) coordinates have acceptably small deviations from the ideal. In that case the Newtonian relationships between energy, momentum, work and force must be taken to hold. Energy conservation can only be local in any case without action at a distance.
 
Last edited:
  • #21
PeterDonis said:
...you can't change physics by changing frames.

Well said!
 
  • #22
I don't think anyone who has posted here except the OP would suggest that going from the holonomic basis to a local frame basis changes any physics.
 
  • #23
PeterDonis said:
... you can't change physics by changing frames.
However, the observers in the different frames can detect one same thing in the different results. In a non-inertial frame, the observer can detect "time varying" and acceleration of the ball in the radial direction. He can calculate this acceleration from "time varying". Another observer in an inertial frame can not detect "time varying", and acceleration of the ball in the radial direction (no contrifugal forece). I think both are correct.
 
  • #24
Somsak said:
I think both are correct.

They're both correct as long as it's clear that "acceleration" means "coordinate acceleration", and "time varying" means "relative to the chosen coordinates". But coordinate-dependent quantities don't tell you about the physics; only invariant quantities, that don't depend on the coordinates you choose, tell you about the physics.
 

FAQ: Relativistic centripetal force is a byproduct of time

1. What is relativistic centripetal force?

Relativistic centripetal force is a force that acts on an object in circular motion, pulling it towards the center of the circle. It takes into account the effects of relativistic time dilation, which means that the force is affected by the object's speed and the passage of time.

2. How is time related to centripetal force?

Time is related to centripetal force through the concept of relativistic time dilation. As an object moves faster, time slows down for that object. This means that the force acting on the object also changes, as it is affected by the object's speed and the passage of time.

3. Can you give an example of relativistic centripetal force?

One example of relativistic centripetal force is the force that keeps a satellite in orbit around a planet. The satellite is moving at a high speed, causing time to slow down for it. This results in a change in the force acting on the satellite, allowing it to maintain its circular orbit.

4. How does relativistic centripetal force differ from classical centripetal force?

Relativistic centripetal force takes into account the effects of time dilation, while classical centripetal force does not. This means that the force acting on an object in circular motion is calculated differently in the two theories, resulting in different values for the force.

5. Why is understanding relativistic centripetal force important?

Understanding relativistic centripetal force is important because it allows us to accurately calculate and predict the motion of objects at high speeds. This is particularly relevant in fields such as astrophysics, where objects are often moving at speeds close to the speed of light.

Similar threads

Replies
11
Views
857
Replies
8
Views
2K
Replies
1
Views
1K
Replies
1
Views
1K
Replies
8
Views
1K
Replies
2
Views
1K
Replies
13
Views
2K
Replies
30
Views
3K
Back
Top