- #1
Somsak
- 7
- 0
From special relativity, we know that
t=t0/(1-v2/c2)1/2
For the object moves as a circle with radius r, the velocity v = w r
Therefore, time varying along radius r as
t=t0/(1-w2 r2/c2)1/2
In this case
ds2= dr2- c2 dt2 = dr2- c2 dt02 /(1-w2 r2/c2)
Since object will move in shortest path in space-time, Dif[ds2,dr] = 0,
and Dif[r,dr] = 1, the above equation will be
0 =2 dr - 2 w2 r dt02 /(1-w2 r2/c2)2
That means the object will move dr due to time varying along radius r as
dr = w2 r dt02 /(1-w2 r2/c2)2 = w2 r dt2 /(1-w2 r2/c2)
Or the object will move with accelleration as
dr/dt2 = w2 r /(1-w2 r2/c2)
This accelleration is look like acting by centrifugal force.
t=t0/(1-v2/c2)1/2
For the object moves as a circle with radius r, the velocity v = w r
Therefore, time varying along radius r as
t=t0/(1-w2 r2/c2)1/2
In this case
ds2= dr2- c2 dt2 = dr2- c2 dt02 /(1-w2 r2/c2)
Since object will move in shortest path in space-time, Dif[ds2,dr] = 0,
and Dif[r,dr] = 1, the above equation will be
0 =2 dr - 2 w2 r dt02 /(1-w2 r2/c2)2
That means the object will move dr due to time varying along radius r as
dr = w2 r dt02 /(1-w2 r2/c2)2 = w2 r dt2 /(1-w2 r2/c2)
Or the object will move with accelleration as
dr/dt2 = w2 r /(1-w2 r2/c2)
This accelleration is look like acting by centrifugal force.
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