# Relativistic cyclotron frequency

1. May 16, 2008

### jdstokes

Since the acceleration is transverse to the velocity, should we consider the transverse mass in the formula $mv^2/r$ ie

$\gamma \frac{mv^2}{r} = qvB \implies \frac{v}{\sqrt{1-(v/c)^2}} = \frac{qBr}{m}$?

2. May 17, 2008

### lzkelley

How can you express the centripetal force in terms of momentum (with other terms)?
How is the relativistic momentum?

3. May 17, 2008

### pmb_phy

Yes. But just to be clear, using your symbols, the transverse mass = gamma*m.

Pete

4. May 17, 2008

### pam

It's clearer in terms of momentum pv/r=qvB-->p=qBr.