Relativistic Particle Speed Approximation using Total Energy

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Homework Statement


Show that, for an extremely relativistic particle, the particle speed u differs from the speed of light c by
$$ c - u = (\frac {c} {2}) (\frac {m_0 c^2} {E} )^2, $$ in which ##E## is the total energy.

Homework Equations


I'm not sure what equations are relevant. This problem was listed at the end of a chapter that included:
$$ m = \gamma m_0, $$
$$ p = \gamma m_0 u, $$
$$ E = m_0 c^2 + K, $$
$$ E^2 = (pc)^2 + (m_0 c^2)^2, $$
$$ dE/dp = u = \frac {pc^2} {E}. $$

The Attempt at a Solution



I have tried to combine/manipulate the above equations into the desired expression, or something similar that I could then use a high-speed approximation on, but I've had no luck. A hint to get me going would be appreciated.
 
on Phys.org
Can you show us what you tried instead of saying "a few things"?

Clearly, you will not get the expression directly since it is a high speed approximation. You will need to extract u from somewhere and then use that some quantity is much smaller than another quantity in the relevant limit.
 

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