Relativistic standing wave electrons?

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SUMMARY

The discussion centers on the relativistic effects in quantum chemistry, specifically regarding electrons as standing waves. It is established that while electrons exhibit standing wave characteristics, they still possess momentum, which is quantified by the first-order correction to their energy, represented as ##- \hat{p}^4 / 8 m^3 c^2##. The conversation clarifies that the wavefunction of an electron encapsulates its momentum probability distribution, allowing for non-zero momentum despite the average being zero. This highlights the complexity of electron behavior in heavy elements where relativistic speeds are attained.

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Garlic
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Quote from the wikipedia article of relativistic quantum chemistry:
"... These corrections affect the electrons differently depending on the electron speed relative to the speed of light. Relativistic effects are more prominent in heavy elements because only in these elements do electrons attain relativistic speeds"

I don't understand this. How can there be relativistic quantum chemistry effects if the electrons that orbit atoms are standing waves?
 
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The expectation value ##\langle \hat{p}^2 \rangle \neq 0##, so while it is a standing wave, the electron has momentum. Actually, the first-order correction to the energy of the electron due to relativistic momentum is ##- \hat{p}^4 / 8 m^3 c^2##.
 
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Garlic said:
How can there be relativistic quantum chemistry effects if the electrons that orbit atoms are standing waves?
I have got the impression that due to your depiction of an electron as a standing wave, you assume that it stands still around the nucleus. The thing is, that "standing wave" is the wavefunction of the electron. This wavefunction contains the information about the momentum probability distribution around the nucleus. Despite the average momentum being zero, the electron can actually be spotted moving when its momentum is being measured. So, it can have non-zero momentum actually.
EDIT: DrClaude beats me to it.
 
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