Find Rest Mass of Composite Particle After Collision

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SUMMARY

The discussion focuses on calculating the rest mass of a composite particle formed after a collision between a moving particle of rest mass m and kinetic energy 2mc² and a stationary particle of rest mass 2m. The initial velocity of the moving particle is determined to be v1 = sqrt(2/3)c. The conservation of momentum and energy principles are applied to derive the equations needed to find the rest mass M of the composite particle. The participants emphasize the importance of correctly accounting for energy contributions and suggest using the equation E=γmc² for simplification.

PREREQUISITES
  • Understanding of relativistic energy equations, specifically E = mc² and E² = (mc²)² + (pc)²
  • Knowledge of momentum conservation in relativistic collisions
  • Familiarity with Lorentz factor (γ) and its application in relativistic physics
  • Basic algebra skills for solving equations with multiple variables
NEXT STEPS
  • Study the derivation and application of the Lorentz factor (γ) in relativistic physics
  • Learn about conservation laws in relativistic collisions, focusing on momentum and energy
  • Explore examples of composite particle mass calculations in high-energy physics
  • Investigate the implications of relativistic effects on particle interactions
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Students and educators in physics, particularly those focusing on relativistic mechanics, as well as researchers interested in particle collisions and composite particle dynamics.

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Homework Statement


A particle of rest mass m and kinetic energy 2mc^c strikes and sticks to a stationary particle of rest mass 2m. Find the rest mass M of the composite particle


Homework Equations


E = mc^2 + KE
E^2 = (mc^2)^2 + (pc)^2
p = mv/sqrt(1-v^2/c^2)


The Attempt at a Solution


For finding the initial velocity of the moving particle:
2mc^2 = KE = mc^2/sqrt(1-v^2/c^2) - mc^2
m's cancel
and when solving for v, you get v1 = sqrt(2/3)c

To find M, I tried using conservation of momentum and energy.
p1 = p2
mv1/sqrt(1-v1^2/c^2) + 2m*0 = Mv2/sqrt(1-v2^2/c^2)
I can't seem to find a way to make the equation only have one unknown.
 
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Where's your conservation of energy equation?
 
E1 = E2
(mc^2)^2 + (cmv1/sqrt(1-v1^2/c^2))^2 = (Mc^2)^2 + (cMv2/sqrt(1-v2^2/c^2))^2
 
That's not quite right. You forgot the energy of the stationary mass. Also, to simplify the algebra, you might want to use E=γmc2 rather than breaking out the rest energy and momentum contributions separately.
 
so it would be
(mc^2)^2 + (cmv1γ1) + 2mc^2 = (Mc^2)^2 + (cMv2γ2)^2?
how would that give me a function of just v2 or M?
 
No, that's still not right. It doesn't work out unit-wise. You have quantities equal to E2, not E. Plus you're making it more complicated than it needs to be. You can calculate the total energy of the system before the collision just by adding up a few quantities you were given.

You have two equations and two unknowns (M and v2). Now it's just a bunch of algebra to solve for them.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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