Remove a force, what would be the resultant

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When the 1000N force acting to the left is removed from the packing crate, the remaining forces are 300N to the right and the friction force. Since the crate is at rest, the friction force must balance the applied forces, which means it would adjust to 300N to the left to counteract the 300N force to the right. Therefore, the resultant force acting on the crate is zero. The reasoning presented confirms that the friction force compensates for the rightward force, leading to no net movement.
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Homework Statement


A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 1000N to the left, 300N to the right, and friction. The weight of the crate is 500N. If the 1000N force is removed, the resultant force acting on the block is

A) zero
B) 300 N to the left
C) 300 N to the right
D) 500 N to the left
E) impossible to determine from the information given.


The Attempt at a Solution



I would say E) since I have no info about the friction. Could you please confirm.

Thank you
 
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It's not brilliantly worded, but I think the clue is when it says that the 'crate *rests* on a horizontal surface'. i.e. it isn't moving. That should give you some info about the friction force.
 
Alright so when the crate is resting the friction would be 700.

If we remove the 1000 N force, the friction would be to the opposite direction and decrease to 300 to cancel the right force.

The resultant force would A) zero.

Is there any problem in this reasoning.
 
Looks fine to me!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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