Remove a force, what would be the resultant

  • Thread starter Thread starter ammoun
  • Start date Start date
  • Tags Tags
    Force Resultant
Click For Summary

Homework Help Overview

The problem involves a packing crate on a horizontal surface subjected to multiple horizontal forces, including a significant force to the left, a smaller force to the right, and friction. The query centers on determining the resultant force when one of the forces is removed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the crate being at rest, which suggests a balance of forces, and question the role of friction in determining the resultant force when the 1000N force is removed.

Discussion Status

Some participants have offered reasoning regarding the friction force and its relationship to the forces acting on the crate. There is an exploration of different interpretations of the problem, particularly concerning the effect of removing the 1000N force.

Contextual Notes

There is uncertainty regarding the friction force, as it is not explicitly provided in the problem statement, leading to differing conclusions about the resultant force.

ammoun
Messages
5
Reaction score
0

Homework Statement


A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 1000N to the left, 300N to the right, and friction. The weight of the crate is 500N. If the 1000N force is removed, the resultant force acting on the block is

A) zero
B) 300 N to the left
C) 300 N to the right
D) 500 N to the left
E) impossible to determine from the information given.


The Attempt at a Solution



I would say E) since I have no info about the friction. Could you please confirm.

Thank you
 
Physics news on Phys.org
It's not brilliantly worded, but I think the clue is when it says that the 'crate *rests* on a horizontal surface'. i.e. it isn't moving. That should give you some info about the friction force.
 
Alright so when the crate is resting the friction would be 700.

If we remove the 1000 N force, the friction would be to the opposite direction and decrease to 300 to cancel the right force.

The resultant force would A) zero.

Is there any problem in this reasoning.
 
Looks fine to me!
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
1K
Replies
20
Views
2K
Replies
6
Views
3K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K
Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
10K