A=[0 -9; 1 -6]
Can this matrix be diagonalized?
The Attempt at a Solution
det(A-[itex]\lambda[/itex]I)=0 gives the eigenvalues of the matrix and yields two eigenvalues that are equal, [itex]\lambda[/itex]= -3
A matrix with repeating eigenvalues are defective and can therefore NOT be diagonalized.
I would further say that rank(A)=1 and nullity(A)=n-rank(A)=2-1=1.... Matlab does not agree with me.... what is wrong with my reasoning here?