Representing Airy's function as a power series

1. Apr 28, 2012

Ratpigeon

1. The problem statement, all variables and given/known data
Find the first five non-zero terms of the power series solution to

2. Relevant equations

... calculus in general?
and the taylor expansion of y(x) is - assuming remainder term is zero:
$\sum$y(n)(-2)/n! *(x+2)n (n from 0 to infinity)
and y''(x) is:
$\sum$y(n)(-2)/(n-2)! *(x+2)n-2 (n from 2 to infinity
3. The attempt at a solution
I let x'=x+2, giving:
$\sum$y(n)(-2)/(n-2)! *(x')n-2-x'$\sum$y(n)(-2)/n! *(x+2)n +2$\sum$y(n)(-2)/n! *(x+2)n
(parameters of first sum are from 2 to infinity, of second two sums from 0 to infinity)
But I'm not sure what to do from here - do I need to find y?

2. Apr 28, 2012

MathematicalPhysicist

You know already two terms, namely: y(-2) , y'(-2)(x+2).

Now in order to find the other non-zero terms, just use your ODE, equate terms with the same powers of x^n to zero, and from there you can find a recurrence relation that will help you find the other terms.

Post back if your'e still stuck.

3. Apr 30, 2012

Ratpigeon

I get a recurrence relation:
a_(n+3)=[a_n-2a_(n+1)-1]/(n+3)(n+2)
but I don't think that can be right, because I need to comment on the convergence...