Representing Sequence 1*3*5*7*9... with Factorials for Calculator Use

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The discussion focuses on representing the odd number sequence 1*3*5*7*9... (2n-1) using factorials for calculator input. It suggests that the product can be expressed as (2n - 1)! divided by the product of the even numbers (2*4*6...*(2n - 2)). Participants explore methods for simplifying the expression to facilitate calculator entry without listing each term. A suggestion is made to factor out a 2 from each term in the denominator to streamline the calculation. The conversation emphasizes finding efficient ways to compute this sequence using factorials.
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is there a way to represent the sequence 1*3*5*7*9...(2n-1) for n>=1 with a factorial if not is thre a way to input that sequence ino a calculator with somthing
 
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1*3*5*7*9...*(2n-1) = (2n - 1)!/(2*4*6*...*(2n - 2))
 
ok is there a way to enter this into a ti without listing
 
Try factoring a 2 out of each term in the denominator of Mark's post
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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