Residual electron-electron interactions, atomic terms

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SUMMARY

The discussion focuses on the atomic term splitting of the excited-state configuration 1s22s22p63s23p64s23d14p1 due to residual electron-electron interactions. The calculated quantum numbers yield the pairs (L, S) as (1,0), (1,1), (2,0), (2,1), (3,0), and (3,1). The total degeneracy of these terms is confirmed to be 60, calculated using the formula (2L+1)(2S+1), which aligns with the expected number of states derived from the quantum numbers of the valence electrons.

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Homework Statement


An atom with an excited-state configuration
1s22s22p63s23p64s23d14p1
With residual electron-electron interactions are taken into account, this configuration splits into atomic terms. List these terms labelled by their L and S quantum numbers

Homework Equations


L=|l1-l2|, |l1-l2|+1,..., l1+l2-1, l1+l2
S=|s1-s2|, |s1-s2|+1,..., s1+s2-1, s1+s2

The Attempt at a Solution


With 3d14p1open would give l1=2 s1=1/2 and l2=1 s1=1/2
Thus L = 1, 2 and 3 and S = 0 and 1. Which give the pairs

(1,0)
(1,1)
(2,0)
(2,1)
(3,0)
(3,1)

Is this correct?

If these are correct then I looked at the degeneracy of each of the terms above and total degenerate states would be 60. How can I confirm that this agrees with the number expected from the l and s quantum numbers of the two valence electrons in the configuration above?
 
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From my question above can I look at (2L+1)(2S+1)? Is there another way from l and s
 
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