Residue of e^(az)/(1+e^z)^2 at I Pi

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SUMMARY

The residue of the function e^(az)/(1+e^z)^2 at the point I Pi can be determined using the Cauchy's kth Integral formula and Laurent series expansion. A substitution of u=e^z initially led to a residue of 0, indicating that u-substitution is not effective for line integrals in this context. The correct approach involves expanding e^(az) and (1+e^z)^2 as series around I Pi and focusing on the coefficient of 1/(z-I Pi) to find the residue accurately.

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lunde
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Homework Statement



I need to find the residue of e^(az)/(1+e^z)^2 at I Pi. For some reason this is such much harder than I thought it was going to be. Mathematica is not even helping :(.

Homework Equations



Cauchy's kth Integral formula.

The Attempt at a Solution



I made an attempt at doing a u substitution of u=e^z, but I ended up with a residue of 0, which was not what I was expecting. All this lead me to believe that you probably can't use u-substitution strategies with line integrals and expect them to work.
 
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Try expanding the function as a Laurent series. Use the fact that

[tex]e^{az} = e^{a(z-i\pi+i\pi)} = e^{ia\pi}e^{a(z-i\pi)}[/tex]

Don't forget to expand both exponentials (in the original function) as series. Remember that all you're interested in is the coefficient of 1/(z-iπ), so just concentrate on the terms that will contribute to that.
 
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