Resistance and Ohm's Law Problem

Click For Summary
SUMMARY

The discussion focuses on calculating the resistance of a solid cube of silver and determining the average drift speed of electrons under a potential difference. The resistance is calculated using the formula R = ρℓ / A, where ρ is the resistivity of silver, and the final answer is 777 nΩ. For the drift speed, the relevant equation J = nqvd is utilized, leading to an average drift speed of 3.28 μm/s when a potential difference of 1.00 x 10-5 V is applied.

PREREQUISITES
  • Understanding of Ohm's Law and resistance calculations
  • Familiarity with the concept of resistivity and its significance in electrical conductivity
  • Knowledge of current density and its relationship to drift speed
  • Basic skills in manipulating algebraic equations for physics problems
NEXT STEPS
  • Research the resistivity values of various materials, focusing on metals like silver
  • Learn about the relationship between current density and drift speed in conductive materials
  • Explore advanced applications of Ohm's Law in circuit analysis
  • Study the impact of temperature on the resistivity of materials
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and electrical properties of materials, as well as educators looking for practical examples of resistance and drift speed calculations.

clairez93
Messages
113
Reaction score
0

Homework Statement



A solid cube of silver (density = 10.5 g/cm^3) has a mass of 90.0 g. (a) What is the resistance between the opposite faces of the cube? (b) If there is one conduction electron for each silver atom, what is the average drift speed of electrons when a potential difference of 1.00 x 10^-5 V is applied to opposite faces? (The atomic number of silver is 47, and its molar mass is 107.87 g/mol)



Homework Equations



(listing all the equations given in the section this problem is relevant to)

J = \sigmaE
J = nqv_{d}
R = \ell / \sigmaA = \DeltaV / I
\rho = 1 / \sigma
R = \rho\ell / A

The Attempt at a Solution



I am completely clueless, at how to start. I think I'll have to use one of the R formulas somehow, but there seems to be too many unknown variables if I try to use any of those. Could someone help me get started?

The book's answer is (a) 777 n\Omega (b) 3.28 \mum/S
 
Physics news on Phys.org
Hi clairez93,


About there seeming to be too many unknowns, I would guess that they want you to look up the resistivity of silver; you should have a table of those values in your book. Once you have that, the other values in the problem will be all you need to work with.
 
R = \rho\ell / A
I am thinking this is the one I will need to use. For \rho I think I will need to look up resistivity. For ell and A, I will need to use the density and mass to get a volume number, I believe, correct?

I'm not sure how to figure out prat b for a drift speed though. I don't see a formula in the section the problem is supposed to belong to for a drift speed. Is there a certain formula I should be using?
 
clairez93 said:
R = \rho\ell / A
I am thinking this is the one I will need to use. For \rho I think I will need to look up resistivity. For ell and A, I will need to use the density and mass to get a volume number, I believe, correct?

That's sounds right.

I'm not sure how to figure out prat b for a drift speed though. I don't see a formula in the section the problem is supposed to belong to for a drift speed. Is there a certain formula I should be using?


One of the formulas you listed in the relevant equations has the drift speed in it. There is a very similar formula that has the current instead of the current density that might be a bit more straightforward.
 
Part A:

R = \rhor / A

Part B:

J = I / A = nqv_{d}

Hope this is still useful.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 15 ·
Replies
15
Views
10K
  • · Replies 2 ·
Replies
2
Views
30K
  • · Replies 38 ·
2
Replies
38
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K