Resistance-current characteristic in the case of filament lamp (investigation)

Click For Summary
The investigation focused on measuring current at various voltage levels in a filament lamp to observe both ohmic and non-ohmic behavior. The experiment utilized an ammeter, voltmeter, filament lamp, and connecting wires to gather data. Internal resistances were identified as a significant source of error, affecting the accuracy of measurements. Suggestions included creating a circuit diagram to illustrate proper connections and ensuring the voltmeter is connected directly across the lamp to measure accurate voltage. Overall, addressing these internal resistances and measurement techniques could enhance the reliability of the results.
eida
Messages
2
Reaction score
0
Changing voltage - independent variable
current flowing - independent variable
The investigation was aimed at measuring current at different potential differences, before the filament lamp started to shine and when it was shining so as to observe both ohmic and non-ohmic behaviour. Also after calculating the resistance, the characterisitc
between it and current was to be analyzed.
Anyway, the ammeter, voltmeter, filament lamp, wires and clips were used.

Hence, my question is arising, do you have any ideas (except internal resistances), what could cause occurring of some errors (systematic or random) and how it could be improved ?
 
Physics news on Phys.org
Hi eida,

Internal resistances cause the main problem.
Make a circuit diagram, show how would you connect the voltmeter and ammeter to the lamp. Remember, the ammeters have internal resistance of several ohms, comparable to the resistance of the filament. You can check it. At the same time, the internal resistance of the voltmeter is high compared to the filament. It is important that you measure the voltage across the lamp, so connect the voltmeter directly to the terminals of the lamp. I would like to see the measuring arrangement.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
6
Views
3K