Resistance Force: 49 kg Diver Dropping 12 m

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Homework Help Overview

The problem involves a 49 kg diver dropping from a height of 12 m and coming to rest 5 m below the water's surface. Participants are tasked with determining the average resistance force exerted by the water on the diver.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating potential energy at the diving height and its conversion to kinetic energy upon entering the water. There are questions about how to apply the work-energy principle to find the resistance force.

Discussion Status

Several participants have attempted calculations for potential energy and resistance force, with some expressing uncertainty about their results. There is a recognition of the need to consider the total distance fallen, including the depth below the water's surface, leading to further exploration of the problem.

Contextual Notes

Participants note discrepancies in calculated values and the feedback from a submission website, indicating a lack of clarity on the correct answer. There is also mention of a potential mistake in the initial height used for calculations.

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Homework Statement



A 49.0 kg diver steps off a 12.0 m high diving board and drops straight down into the water. If the diver comes to rest 5.0 below the surface of the water, determine the average resistance force exerted on the diver by the water.

Homework Equations



PE=m*g*h

KE=1/2mv^2

The Attempt at a Solution



?
 
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What is the potential energy of the diver 12m above the water? The water will have to do an equivalent amount of work over a distance of 5m to stop the diver.

Remember: W = F*d (where W = work, F is force, d is distance)
 
Jimmy said:
What is the potential energy of the diver 12m above the water

So I should find the PE of the diver at 12m?
PE=49*12*9.81
PE=5768.28?

The question asks to determine the average resistance force exerted on the diver by the water.

So I would use W=F*D?

How do I put this all together now?
 
Vision5 said:
So I should find the PE of the diver at 12m?
PE=49*12*9.81
PE=5768.28?
That's correct. Don't forget the unit of energy: 5768.28 J (Joules)

Now that potential energy will be converted to kinetic energy as the diver falls. At the surface of the water, the diver will have 5768.28 J of KE.

The question asks to determine the average resistance force exerted on the diver by the water.

So I would use W=F*D?

How do I put this all together now?
As I stated before, the water will have to do an equivalent amount of Work (5768.28 J) to stop the diver- both work and energy are measured in Joules. Knowing that this happens over a distance of 5 meters, you can plug the known values into the Work formula and and solve for F:
W = F*D

F = W/D
 
I don't know if I'm just not doing something right or what it is but, i calculated PE:

PE=5768.28 J

Then you told me I should plug this in for work:

F=5768.28/5
F=1135.65 N

unfortunately this is not the correct answer... Any ideas what it could be??
 
I'm getting 1153.65 N. I'm sure your 1135 is a typo. What's given as the correct answer?
 
Yes that was a typo, but I don't know the correct answer I have to submit to a website and it only let's me know whether my answer is correct or not and it is telling me that 1153.65 N is not correct. Are there any other approaches to this problem?
 
Yes. I made a mistake. We need to consider the 5m below the water as well as the 12m in the PE calculation. Use 17m since that is the actual height the diver falls.

Sorry about that. Stupid mistake...
 
Its 1634.34 N

Thanks so much for the help.
 
  • #10
Your welcome. I apparently need a little practice myself. :D
 

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