What is the cause of a lightbulb blowing when switched on?

In summary, the lightbulb with a rating of 60 watts and 230 volts has a resistance of approximately 882 ohms. However, when checked with a multimeter, it reads 65 ohms, which is due to the positive temperature coefficient of the filament. When the lightbulb is at its operating temperature, the resistance increases to about 880 ohms. It is also noted that when a lightbulb blows, it is usually due to the lower resistance at the initial stage, allowing it to draw more current and eventually overheat and melt. The discussion also touches on the accuracy of the multimeter used and the importance of sensitivity when measuring voltage, with the recommendation to use a digital meter with a high input impedance
  • #1
phlegmy
120
0
[SOLVED] resistance of a lightbulb?

hey dudes
so I've a lightbulb that says 60w 230v
so i figure it draws 60/230 amps
so i figure its resistance is 60w/((60/230)^2), which gives me 882 ohms

so i checked this light bulb with a multimeter and it reads 65 ohms!

so i figure that at its "operating temprature" the resistance increases to around 880 ohms? is this correct

also I've noticed that when a lightbulb blows its ususally just as you switch it on,
is this because it has lower resistance initially which allows it to draw more current and it ends up overheating and melting??

thanks for your help, (or should i go buy a new multimeter, this one only cost me €6!) (thats not 6 factorial, its just six):)
 
Engineering news on Phys.org
  • #2
phlegmy said:
hey dudes
so I've a lightbulb that says 60w 230v
so i figure it draws 60/230 amps
so i figure its resistance is 60w/((60/230)^2), which gives me 882 ohms

so i checked this light bulb with a multimeter and it reads 65 ohms!

so i figure that at its "operating temprature" the resistance increases to around 880 ohms? is this correct

also I've noticed that when a lightbulb blows its ususally just as you switch it on,
is this because it has lower resistance initially which allows it to draw more current and it ends up overheating and melting??

thanks for your help, (or should i go buy a new multimeter, this one only cost me €6!) (thats not 6 factorial, its just six):)
Exactly correct on both accounts! A common tungsten light bulb filament runs at 2800K, for a resistance ratio of about 15:1 according to
http://hypertextbook.com/facts/2004/DeannaStewart.shtml
This is close to the ratio you observe.

I've never heard of such a cheap multimeter, must be used, yes? Figure its accuracy is inversely proportional to its price divided by the new price of a good one... :eek:)
 
  • #3
Determining the resistance of a bulb with a meter is inaccurate. The filament has a positive temp. coefficient. This means its resistance rises with temperature. When cold you'll get a few ohms of resistance, but at operating temperature, expect it to rise dramatically. In case you're wondering the lamp at 60Hz can be considered a purely resistive load.

Thats a cheap meter! Get one with a high sensitivity.
 
  • #4
thanks guys,

the meter is new, i bought it to use with my final year project (mechanical engineering) last year. its a "category II".#
i checked it against expensive ones in the electronics and control lab in college,
and for the comparisons i did it worked pretty well, i can't remember any figures but i tested it using about 5 or 6 resistors and, and it was measuring mV accractly aswell!

found one on the internet just now http://www.multimeterwarehouse.com/dt830bf.htm
for8 dollars. i bought mine in a hardware and tools shop, it was the only mm in the whole store (i think they must have ordered a batch of them about 5 years ago and were just waiting to be rid of em! it was in a type of bargain box which just had a big mix of stuff from spririt levels, allen keys, drill bits, and 1 multimeter!)
 
  • #5
The DT830B is a pretty good meter. I use to use it quite extensively in the lab and still use it when I need to do measurements. You'll only need to worry about meter sensitivity when dealing with analog meters. Its important for your meter to have a high input impedance when measuring voltage so it doesn't introduce a loading effect into the circuit. Sensitivity comes into the play because the product of sensitivity and your full scale voltage setting gives you your meter's input impedance.

But you won't need to worry about sensitivity if you have a digital meter, since these meters have high input impedances in the order of mega ohms. Generally you'll run into trouble when measuring the voltage across a component that has a resistance that is equal to or greater than your meter's input impedance. A nice ratio (component resistance: meter resistance) would be like 1:10 or even higher! You will have to pay attention to this if you want reliable voltage readouts.
 

What is the resistance of a lightbulb?

The resistance of a lightbulb is a measure of the opposition to the flow of electric current through it. It is typically measured in ohms (Ω).

How is the resistance of a lightbulb determined?

The resistance of a lightbulb can be determined by using Ohm's Law, which states that resistance is equal to voltage divided by current (R = V/I). It can also be measured using a multimeter.

What factors affect the resistance of a lightbulb?

The resistance of a lightbulb can be affected by several factors, including the material of the filament, the length and thickness of the filament, and the temperature of the filament. It can also be affected by the type and quality of the wiring and connections in the circuit.

Why does the resistance of a lightbulb increase as it ages?

As a lightbulb ages, the material of the filament gradually breaks down, causing it to become thinner and more brittle. This leads to an increase in resistance, which in turn causes the lightbulb to produce less light and eventually burn out.

How does the resistance of a lightbulb impact its energy consumption?

The resistance of a lightbulb plays a significant role in its energy consumption. A higher resistance means that more energy is needed to produce the same amount of light, resulting in higher energy consumption and a higher electricity bill.

Similar threads

  • Electrical Engineering
Replies
1
Views
3K
  • Electrical Engineering
Replies
8
Views
4K
Replies
12
Views
2K
  • Electrical Engineering
Replies
8
Views
2K
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
1K
Replies
1
Views
523
  • Electrical Engineering
Replies
8
Views
3K
  • Introductory Physics Homework Help
Replies
17
Views
7K
Back
Top