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**[SOLVED] resistance of a lightbulb???**

hey dudes

so i've a lightbulb that says 60w 230v

so i figure it draws 60/230 amps

so i figure its resistance is 60w/((60/230)^2), which gives me 882 ohms

so i checked this light bulb with a multimeter and it reads 65 ohms!!!!!

so i figure that at its "operating temprature" the resistance increases to around 880 ohms? is this correct

also i've noticed that when a lightbulb blows its ususally just as you switch it on,

is this because it has lower resistance initially which allows it to draw more current and it ends up overheating and melting??

thanks for your help, (or should i go buy a new multimeter, this one only cost me €6!) (thats not 6 factorial, its just six):)