Resistence and double stranded wire.

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Homework Help Overview

The discussion revolves around the resistance of a wire that has been cut in half and rejoined to form a double-stranded wire. The original wire is 2.0 meters long with a resistance of 0.20 ohms. Participants explore the implications of this transformation on the wire's resistance, particularly focusing on the concept of parallel resistors and the relationship between length and cross-sectional area.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the resistance of the original wire and its halves, questioning how the rejoining affects the overall resistance. Some suggest considering the two strands as parallel resistors, while others explore the implications of doubling the cross-sectional area.

Discussion Status

The conversation has progressed with some participants providing insights into the relationship between resistance, length, and cross-sectional area. There is a recognition of the parallel resistor concept, and some clarification has been offered, though not all participants fully agree on the implications.

Contextual Notes

Participants note the absence of information regarding the wire's diameter, which is seen as a potential limitation in fully resolving the problem.

zebra1707
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Homework Statement



I have been stuck with a problem regarding the resistance of a wire that is 2.0 meters long, has a resistance of 0.20 ohm. The wire has been cut in half and then the two ends of the new wires joined together to make a double standed wire.

We don't know what the diameter of the wire is - which I find a bit strange. I have worked our what the resistance of the two halves would be (0.10 ohm) - that is okay. Its the new double strand that has got me stumped.


Homework Equations





The Attempt at a Solution



Cheers Petra d.
 
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zebra1707 said:

Homework Statement



I have been stuck with a problem regarding the resistance of a wire that is 2.0 meters long, has a resistance of 0.20 ohm. The wire has been cut in half and then the two ends of the new wires joined together to make a double standed wire.

We don't know what the diameter of the wire is - which I find a bit strange. I have worked our what the resistance of the two halves would be (0.10 ohm) - that is okay. Its the new double strand that has got me stumped.

Welcome to PF.

If you know the resistance of 1 strand, then maybe two strands could be figured as parallel resistors?
 
Thankyou for the welcome

Its the resistance of the "new" double stranded wire that has got me stumped.

Many thanks for taking the time to reply.

Cheers Petra d.
 
zebra1707 said:
Thankyou for the welcome

Its the resistance of the "new" double stranded wire that has got me stumped.

Many thanks for taking the time to reply.

Cheers Petra d.

Whether you consider that they are || resistors, or simply that you have doubled the cross sectional area of both resistors - halving the equivalent resistance - I think you get the same result.
 
Hi there

Thank you for the reply. Not sure that I understand your response.

I think what you are saying is that the resistance of the wire will not change - even though it is now double-stranded??

Full strand of wire is 2.0 meters = 0.2 ohm resistance
1/2 stand is 1.0 meters = 0.1 ohm (I understand this relationship)

1/2 stands have now become double-strand (still 1.0 meter in length) - what is the resistance and the relationship. Note that I do not have a diameter of the wire.

Cheers Petra



LowlyPion said:
Whether you consider that they are || resistors, or simply that you have doubled the cross sectional area of both resistors - halving the equivalent resistance - I think you get the same result.
 
No. You don't understand.
Yes you chopped the wire in half.
Yes the length is now half and each resistor's resistance is half.

But you twisted them together - essentially made them parallel.
The equivalent resistance of that would be given by calculating the resistance for 2 parallel resistors.

1/Req = 1/R + 1/R = 1/.1 + 1/.1 = 20

Req = 1/20 = .05

Looking at it another way, a resistor's resistance is proportional to length. The longer it is the greater the resistance. It is inversely proportional to cross sectional area.The greater the area, the less the resistance. While it's true you don't know the diameter, you do know that since you have now 2 cross sections of the same thing it is twice as much area - whatever it is.

So while R = ρ*L/A if you take 1/2 the original L and double the A you get

Req = ρ*(L/2)/(2A) = 1/4*ρ*L/A = 1/4*R = 1/4*.2 = .05

http://en.wikipedia.org/wiki/Electrical_resistance#DC_resistance
 
HI there

Many thanks - this has clarified it for me.

Cheers Petra d.
 

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