A ball is thrown at 32m/s vertically what is the max height the ball can attain.
no equation is given except initial speed
The Attempt at a Solution
so my guess is since the gravity is 9.8m/s^2
if I integrate 9.8m/s^2 = 32 it gives me 2.1396
so after 2.1396 the ball should have its max height.
So I end up with this equation
height = 32*2.1396 - 9.8*2.1396^2
height = 23.60 meters
But I am soo uncertain about my answer, I have to use calculus to resolve it
Thank you for your help