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## Homework Statement

A ball is thrown at 32m/s vertically what is the max height the ball can attain.

## Homework Equations

no equation is given except initial speed

## The Attempt at a Solution

so my guess is since the gravity is 9.8m/s^2

if I integrate 9.8m/s^2 = 32 it gives me 2.1396

so after 2.1396 the ball should have its max height.

So I end up with this equation

height = 32*2.1396 - 9.8*2.1396^2

height = 23.60 meters

But I am soo uncertain about my answer, I have to use calculus to resolve it

Thank you for your help

Jonathan