Resolving parallel and perpendicular to the plane

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SUMMARY

The discussion centers on calculating the force required to keep a 50kg rectangular block from slipping on a rough surface inclined at 0.6 radians, with a static friction coefficient of 0.2. The calculated force needed is 196 N, derived by resolving forces parallel and perpendicular to the inclined plane. The calculation confirms that this force is necessary to counteract the gravitational component acting down the slope and the frictional force. The conclusion is that 196 N is indeed the correct force to apply to the rope.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Knowledge of force resolution in inclined planes
  • Basic principles of Newton's laws of motion
  • Familiarity with trigonometric functions related to angles
NEXT STEPS
  • Study the principles of force resolution in inclined planes
  • Learn about static and kinetic friction coefficients
  • Explore Newton's laws of motion in practical applications
  • Investigate the effects of different angles of inclination on friction
USEFUL FOR

Physics students, engineers, and anyone involved in mechanics or materials science will benefit from this discussion, particularly those focusing on forces and friction in inclined systems.

sara_87
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A rectangular block of mass 50kg is held by a rope on a rough surface inclined at 0.6 radians.
Assume that the coefficient of static friction is 0.2, determine what force needs to be applied to the rope to keep the block from slipping.

I did this by resolving parallel and perpendicular to the plane and found the the force required is196 N. however, I'm not sure of this. can someone please work this out and see if my answer is right.

Thank you!
 
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