Andrew1955 said:
I understand a lazy shisnos example alright. I am still not clear why peculiarities about the speed of light must mean time and length must also change.
If light causes us to perceive weird stuff does this mean that weird stuff is really happening? If we see wave lengths of light as red is red really out there or is there just colourless energy which we interpret and imagine as being red? Do you think the sky is actually blue? The grass is green? These things are only illusions created by the human visual system.
We use light to help us perceive reality. If light tells us time has changed, should be believe that just because 'light says its true'.?
My take on this thorny issue:
Easy way to vaguely understand:
(1) Every timed measurement is pair of simultaneous events (the hand of your clock arriving at a certain tick mark coinciding with the event you are looking at, e.g., the simultaneous events of the hand of your clock moving to a point and, say, the racer you are timing arriving at a point).
(2) If every timed measurement is at minimum a pair of simultaneous events, and simultaneity is not universal, then timed measurements cannot be universal either.
(3) Since everything that moves in a periodic way can be used as a clock (including the motion of the atoms that make you), it seems to follow that time itself cannot be universal as well.
Hard way to vaguely understand:
How fast are you moving right now?
When you are finished considering that question, hopefully you will realize the question is completely meaningless. You are sitting still, on a spinning earth, which is orbiting the sun, which is orbiting the milky way, which is moving with respect to other galaxies, which are themselves moving in a large galaxy cluster, and so on and so on.
In my humble opinion, the first step to figuring this "paradox" out is understanding this concept. Galileo figured it out some time ago: the principle of relativity. So when you get that down, you'll truly realize there is no inherent difference between the person at rest on the train and the person who sees the train fly by (or from the perspective of the train passenger, the person who flies by the train).
That's a big Step 1, I believe.After that, all you have to do is incorporate the idea that all the fastest signals used for communication move at the same maximum speed for all uniformly moving observers (conveniently, the speed of light is this speed). So what happens when you combine "Step 1" with the fact that there is a maximum speed which all observers agree on regardless of how "fast" (remember the question is meaningless in and of itself) they are moving?
Then you can turn to the good old fashioned light clock (and realize that what applies to a light clock must apply to any type of clock as well, because there is nothing magical about them that makes them unique with respect to the laws of physics). This little cognitive tool really does the trick. So, we have both observers agreeing on the speed of light, and we have the principle of relativity. So we can imagine a pulse of light bouncing vertically between two mirrors, and each trip up is a tick, each trip down is a tock. And we can further imagine the clock being held steadily by one observer (so that the other one sees the clock moving). You end up with a straight up and straight down path of the light for the observer holding it, and a triangle shape for the path of light for the other observer. This will actually give you a right triangle if you combine the two. You can use t and T to represent the time that each measures, and it MAY be that the times are the same, and it MAY be that they are not. Don't make the assumption yet.
So, looking at the triangle, you have a hypotenuse of ct, a horizontal line of vt (v is the relative speed between the two observers), and a vertical line of cT. Use the Pythagorean theorem to find the ratio of t to T, i.e., t/T. (c in both cases because all observers agree on the speed of light, and ct and cT because speed times time is distance). Just basic middle school stuff.
(ct)
2 = (vt)
2 + (cT)
2
First divide everything by (ct)
2(1)
2 = (v/c)
2 + (T/t)
2
Now, subtract (v/c)
2
1 - (v/c)
2 = (T/t)
2
Now take the root
√[1 - (v/c)
2 ]= T/t.
We could stop right there and see that the only way T = t is if v is 0, but just to make things look standard, divide by T/t and then divide by √[1 - (v/c)
2 ]:
t/T = 1/√[1 - (v/c)
2 ]
Then multiply by T to get your standard time dilation formula:
t = T/√[1 - (v/c)
2 ] ****
So yeah, if you assume the principle of relativity and the constancy of the maximum speed (which conveniently matches with the speed of light), and then use simple thought experiments like a light pulse clock, you see rather clearly that the two observers are going to disagree on time. Then if you are clever enough to realize that, because of the principle of relativity, this result applies
universally, in all similar instances regardless of where the observer is and how fast s/he is moving, it is clear that anything that can be used to measure time will give measurements of time that depend upon frame of reference. And if you are super clever, you will note that the atoms your body is made of, the electrical pulses in your brain as you think, and every other thing that moves in a way that could conceivably be used as a clock, will have the same property of time depending on frame of reference, and then you can make the next logical leap to realize that time itself depends on frame of reference, rather than merely clocks.
Then you can make the next logical leap and consider how you would measure the length of something moving past you, and realize you'd be depending on some sort of signal coming from the edges of the object to your eye, taking a finite amount of time to get there, and once again depending upon simultaneity (to get an accurate length, you need to measure the two ends simultaneously, since the object is moving). From there you will realize that length contraction will occur according to observers measuring the length of a moving object. And once again, if you understand Galileo's principle of relativity, you will note that your particular frame of reference is not special, and thus the measured length will also necessarily depend on frame of reference (since it depends on simultaneity, which is not universal).Or you could go the simple route and realize that if simultaneity is not absolute than neither can time be absolute.
(****on a somewhat unrelated note, this works for pre-special relativity time as well. All you have to do is assume that c is infinity, and you end up with t = T, like it was in the old days. Or you could assume that v is approximately zero compared to c, making v/c zero in the limit, reducing the thing to t = T again. But of course we know that c is finite and that all inertial observers agree on it, meaning you are stuck with t not being equal to T when v is not equal to zero).