Resonance energy per ring in benzene, napthalene, anthracene

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SUMMARY

The resonance energy per ring in benzene, naphthalene, and anthracene can be determined by dividing the total resonance energy by the number of rings. Benzene has a resonance energy of 36 KCal/mol. Anthracene exhibits the highest stability and resonance energy, followed by naphthalene, leading to the order of resonance energy per ring as anthracene > naphthalene > benzene. This conclusion is drawn from logical reasoning about the stability and structure of these aromatic compounds.

PREREQUISITES
  • Understanding of resonance energy in aromatic compounds
  • Knowledge of benzene, naphthalene, and anthracene structures
  • Familiarity with molar calculations in chemistry
  • Basic concepts of molecular stability and energy
NEXT STEPS
  • Research the resonance energy values for naphthalene and anthracene
  • Learn about the stability factors affecting aromatic compounds
  • Explore the concept of molecular orbital theory in relation to resonance
  • Investigate the implications of resonance energy on chemical reactivity
USEFUL FOR

Chemistry students, organic chemists, and anyone studying the properties of aromatic compounds and their stability.

Krushnaraj Pandya
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Homework Statement


Compare resonance energy per ring in benzene, napthalene and anthracene

Homework Equations


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The Attempt at a Solution


I know Resonance energy of benzene is 36 KCal/mol, I also know anthracene is the most stable followed by napthalene so their resonance energy is in the order anthracene>napthalene>benzene but how do I compare it per ring?
 
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You can always try to divide molar resonance energy by the number of rings.
 
Borek said:
You can always try to divide molar resonance energy by the number of rings.
We aren't provided any data in the exam, we just need to find the increasing order of resonance energy per ring through logical guesswork. The logic for napthalene having lower resonance energy per ring is what I'm looking for
 

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