Resonance - working out damping constant and damping factor

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Homework Help Overview

The discussion revolves around a lab report focused on resonance, specifically the determination of the damping constant and damping factor through experimental data involving amplitude measurements. The original poster describes their approach of plotting amplitude number against the natural logarithm of amplitude.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster graphed amplitude number versus ln(A) and noted the negative gradient, questioning whether this slope corresponds to the damping constant. They express confusion regarding the implications of this negative value. Other participants discuss the relationship between the slope and gamma, and clarify the nature of the amplitude number in relation to time.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the relationships between the variables involved. There is an ongoing exploration of the implications of the graph's slope and its connection to the damping constant, as well as the definition of amplitude number.

Contextual Notes

Participants are navigating the complexities of the equations provided in the homework statement, particularly the assumptions regarding phase and amplitude measurements. There is an emphasis on understanding the definitions and relationships between the variables involved in the resonance context.

Anabelle37
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Homework Statement



I'm doing a lab report on resonance and I'm trying to find the damping constant and damping factor. I measured as many amplitudes(A) for successive oscillations as possible and graphed amplitude number (n) vs. ln(A)

The hint read:
Part 1:Using equation 5, Plot a graph of amplitude number n vs ln(A) (the amplitude in
any units of convenience). The starting amplitude should be marked as n = 0.

Part 2:Now, by assuming that phi = 0, derive an equation for t in terms of wo, gamma and the observed amplitude number n. The starting amplitude corresponds to n = 0, so the next amplitude would be n =1 etc. Once you obtain the equation for t, rewrite equation (5), so that an equation relating n and y is obtained. By taking natural log of both sides, an equation of a straight line can now be obtained. Now do some algebra to obtain expression for gamma interms of the slope of this straight line. Measure the slope of your graph and hence get the value of gamma.

Homework Equations



equation 5: y=(Ce-gamma*t).(cos(w't - phi))

where w' = sqrt(wo2 - gamma2)


The Attempt at a Solution



So I've graphed amplitude number n vs ln(A) and it gives negative gradients. i used this value as my gamma but because its negative value it gives me a value of < 1 for my damping constant, d and d should be >1

is the slope of the graph not meant to be gamma??
i cannot figure out how to do part 2 of the hint (rearranging formulas to get necessary expressions)
 
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Your amplitude is
<br /> A=ce^{-\gamma t}<br />
and
<br /> lnA=lnc -\gamma t<br />
<br /> lnA/dt=-\gamma<br />
You get negative slope from graph
<br /> -|a|<br />
It is equal to
<br /> -|a|=-\gamma<br />
and
<br /> |a|=\gamma<br />
 
Ok thanks heaps.
Just confused about one thing...my graph was amplitude number (n) vs. ln(A) not time versus ln(A). does gamma still equal the positive value of the slope from that graph?
 
Please explain what is amplitude number (n).
n depends on time.
May be you measure amplitude A when cos(w't)=1 and phase is w't=2 pi n.
You could also measure when phase is w't= pi n - when one amplitude is
positive and other negative.
 

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