Resonance - working out damping constant and damping factor

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SUMMARY

The discussion focuses on calculating the damping constant and damping factor in a resonance lab report using the equation y=(Ce-gamma*t)(cos(w't - phi)). The user graphed amplitude number (n) against ln(A) and encountered negative gradients, leading to confusion about the interpretation of gamma. The correct approach involves recognizing that gamma corresponds to the negative slope of the ln(A) graph, and the amplitude number n is dependent on time, specifically when cos(w't) equals 1. The user must ensure that the slope is interpreted correctly to derive a valid damping constant.

PREREQUISITES
  • Understanding of resonance and oscillatory motion
  • Familiarity with logarithmic functions and their properties
  • Knowledge of the damping constant and its significance in physics
  • Ability to manipulate and rearrange algebraic equations
NEXT STEPS
  • Study the derivation of the damping constant from the slope of ln(A) vs. n graphs
  • Learn about the implications of negative slopes in logarithmic graphs
  • Explore the relationship between amplitude, time, and phase in oscillatory systems
  • Investigate the effects of varying damping factors on resonance behavior
USEFUL FOR

Students in physics or engineering, particularly those working on resonance experiments and analyzing oscillatory motion, will benefit from this discussion.

Anabelle37
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Homework Statement



I'm doing a lab report on resonance and I'm trying to find the damping constant and damping factor. I measured as many amplitudes(A) for successive oscillations as possible and graphed amplitude number (n) vs. ln(A)

The hint read:
Part 1:Using equation 5, Plot a graph of amplitude number n vs ln(A) (the amplitude in
any units of convenience). The starting amplitude should be marked as n = 0.

Part 2:Now, by assuming that phi = 0, derive an equation for t in terms of wo, gamma and the observed amplitude number n. The starting amplitude corresponds to n = 0, so the next amplitude would be n =1 etc. Once you obtain the equation for t, rewrite equation (5), so that an equation relating n and y is obtained. By taking natural log of both sides, an equation of a straight line can now be obtained. Now do some algebra to obtain expression for gamma interms of the slope of this straight line. Measure the slope of your graph and hence get the value of gamma.

Homework Equations



equation 5: y=(Ce-gamma*t).(cos(w't - phi))

where w' = sqrt(wo2 - gamma2)


The Attempt at a Solution



So I've graphed amplitude number n vs ln(A) and it gives negative gradients. i used this value as my gamma but because its negative value it gives me a value of < 1 for my damping constant, d and d should be >1

is the slope of the graph not meant to be gamma??
i cannot figure out how to do part 2 of the hint (rearranging formulas to get necessary expressions)
 
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Your amplitude is
<br /> A=ce^{-\gamma t}<br />
and
<br /> lnA=lnc -\gamma t<br />
<br /> lnA/dt=-\gamma<br />
You get negative slope from graph
<br /> -|a|<br />
It is equal to
<br /> -|a|=-\gamma<br />
and
<br /> |a|=\gamma<br />
 
Ok thanks heaps.
Just confused about one thing...my graph was amplitude number (n) vs. ln(A) not time versus ln(A). does gamma still equal the positive value of the slope from that graph?
 
Please explain what is amplitude number (n).
n depends on time.
May be you measure amplitude A when cos(w't)=1 and phase is w't=2 pi n.
You could also measure when phase is w't= pi n - when one amplitude is
positive and other negative.
 

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