What Is the Average Length of a DNA Strand Cut by a Restriction Enzyme?

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SUMMARY

The average length of a DNA strand cut by a restriction enzyme can be calculated using the probability of the enzyme recognizing a specific sequence. In this case, the restriction enzyme recognizes the sequence AAGCCT, which consists of 6 base pairs. The probability of the enzyme reading the correct sequence is (1/4)^6, which equals 1/4096. This indicates that, on average, the length of the DNA strand cut by the enzyme is influenced by this low probability of recognition.

PREREQUISITES
  • Understanding of DNA structure and nucleotide base pairs
  • Knowledge of restriction enzymes and their function in molecular biology
  • Basic probability theory, particularly regarding independent events
  • Familiarity with mathematical calculations involving exponents
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  • Learn about the applications of restriction enzymes in genetic engineering
  • Study probability distributions in biological contexts
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Homework Statement



Homework Statement

I know this is a biology question but this is the most busy forum so I decided to put it here:

I'll make this simple. A restriction enzyme reads a DNA strand containing nucleotide base pairs. It cuts the strand after it reads a sequence of 6 base pairs - AAGCCT. Of course the probability of the enzyme reading the correct base is 1/4. And it needs 6 of them.

So what is the average length of a cut strand? I'm thinking you do (1/4)^6 and this will give you something.. but what?

Thanks for your help in advance...



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The Attempt at a Solution

 
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(1/4)^6 gives you the probability that your enzyme will read the string(tag) correctly and you know the length of your string so combine these number will give you an average length of a cut given that it consists of only this sequence - this is how I understand you.
 

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