Resulstant force pendulum equilibrium position

  • Thread starter binbagsss
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  • #1
binbagsss
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so it continues to move in a circular arc and so must have a resultant centripetal force acting on it which is provided by tension being greater than mg. However at this point its acceleration it's 0.

So is it correct to say that there is no resultant force momentarily, and if this is the case what would be the other force balancing out the centripetal force

Sorry wording isn't too great, thanks alot !
 

Answers and Replies

  • #2
tiny-tim
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hi binbagsss! :smile:
However at this point its acceleration it's 0.

no, its tangential acceleration is 0 …

it still has v2/r centripetal acceleration :wink:
 
  • #3
binbagsss
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hi binbagsss! :smile:


no, its tangential acceleration is 0 …

it still has v2/r centripetal acceleration :wink:

oh right, so going by x proportional to a, so in zero position both are 0.. is this referring to the tangential acceleration?

thanks :)
 
  • #4
tiny-tim
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that's right! :smile:

when we treat something as simple harmonic motion we are treating it as one-dimensional, so the rules about maximum acceleration etc only refer to that dimension :wink:
 
  • #5
binbagsss
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ahh thanks alot :D
 

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