- #1

binbagsss

- 1,233

- 10

So is it correct to say that there is no resultant force momentarily, and if this is the case what would be the other force balancing out the centripetal force

Sorry wording isn't too great, thanks alot !

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- Thread starter binbagsss
- Start date

- #1

binbagsss

- 1,233

- 10

So is it correct to say that there is no resultant force momentarily, and if this is the case what would be the other force balancing out the centripetal force

Sorry wording isn't too great, thanks alot !

- #2

tiny-tim

Science Advisor

Homework Helper

- 25,838

- 255

However at this point its acceleration it's 0.

no, its

it still has v^{2}/r centripetal acceleration

- #3

binbagsss

- 1,233

- 10

hi binbagsss!

no, itstangentialacceleration is 0 …

it still has v^{2}/r centripetal acceleration

oh right, so going by x proportional to a, so in zero position both are 0.. is this referring to the tangential acceleration?

thanks :)

- #4

tiny-tim

Science Advisor

Homework Helper

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- 255

when we treat something as simple harmonic motion we are treating it as one-dimensional, so the rules about maximum acceleration etc only refer to

- #5

binbagsss

- 1,233

- 10

ahh thanks alot :D

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