Resultant Moment of Force Around Point O: 20 Nm Clockwise

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SUMMARY

The resultant moment of forces around point O is calculated to be 20 Nm in the clockwise direction. The calculation involves adding the moments from points A (60 Nm) and B (40 Nm), resulting in 100 Nm, and then subtracting the moment from point C (120 Nm) since it acts in the opposite direction. The correct approach is to define a right-hand coordinate system to avoid confusion with directionality in complex scenarios.

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Saanchi
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Homework Statement


Calculate resultant moment of forces about pt O and state its direction.

Homework Equations


Put the picture. Check it out

The Attempt at a Solution


What I did was :
About A : 60Nm
B: 40 Nm
C : 120Nm.

I'm not sure to add or subtract for resultant. What I did::
Add. A-B as they are in same direction : 60➕40 : 100
Then subtract 120 to it as opposite direction direction

Therfore. 20 Nm

Am I right about the resultant or totally wrong?

Direction : Clockwise.
 

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You are correct. You should specify that it is clockwise around the axis coming out of the page. In complicated situations, you define a right-hand coordinate system. Then your moments around an axis have the appropriate sign and you don't have trouble keeping track of clockwise, counterclockwise around which axis.
 
Last edited:
FactChecker said:
You are correct.
Alright. Thanks :)
 

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