Resultant of two orthogonal vectors

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
9 replies · 3K views
Crystal037
Messages
167
Reaction score
7
Homework Statement
The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations
|a+b|=sqrt(a^2 +b^2 +2ab)
IMG_20200327_160143.jpg

But the answer in my book is given that sec(theta) =3. Where am I going wrong?
 
Physics news on Phys.org
Crystal037 said:
Where am I going wrong?
I think nowhere. So the book answer must be a mistake.
You could come up with a better drawing, though. And a sign of the secant is minus if b = 2a.
 
  • Like
Likes   Reactions: Merlin3189
Maybe I am interpreting the question wrongly. I don't know if that is what the question is supposed to mean.
 
You worked out your interpretation. You think there is an alternative ?
 
Crystal037 said:
Homework Statement:: The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations:: |a+b|=sqrt(a^2 +b^2 +2ab)
Your relevant equation is wrong, unless by ab, you mean the scalar product of vector a and vector b .

As far as a different reading of the problem (Yes, the given statement is ambiguous.):

Rather than one and the other referring to the two orthogonal vectors, perhaps they refer to the resultant and the difference vectors. Is this even possible?
 
SammyS said:
Is this even possible?
If two vectors ##\vec a## and ##\vec b## are orthogonal, then ##\vec a\cdot\vec b=0 \Rightarrow |\vec a + \vec b | = |\vec a - \vec b | ##
 
Stated differently, if the vectors are orthogonal, one can form a ##a\times2a## rectangle with them. One diagonal is the sum, the other is the difference and they have equal magnitudes. There are two angles between the diagonals to be considered, one being the supplementary of the other.
 
One comment about your notation: when the problem says "the magnitude of one is 2 times that of the other", it's not correct to write ##\vec b = 2 \vec a##. That would imply that the two vectors are parallel to each other and not orthogonal.
 
  • Like
Likes   Reactions: SammyS
Crystal037 said:
If magnitude of one is 2 times that of the other, find the value of sec θ.
Try this instead.

If magnitude of one is ##\sqrt{2~} ## times that of the other, find the value of sec θ.
 
  • Like
Likes   Reactions: Lnewqban
SammyS said:
Try this instead.

If magnitude of one is ##\sqrt{2~} ## times that of the other, find the value of sec θ.
Yes then the answer comes as 3.