Resultant of two orthogonal vectors

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Crystal037
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Homework Statement
The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations
|a+b|=sqrt(a^2 +b^2 +2ab)
IMG_20200327_160143.jpg

But the answer in my book is given that sec(theta) =3. Where am I going wrong?
 
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Crystal037 said:
Where am I going wrong?
I think nowhere. So the book answer must be a mistake.
You could come up with a better drawing, though. And a sign of the secant is minus if b = 2a.
 
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Maybe I am interpreting the question wrongly. I don't know if that is what the question is supposed to mean.
 
Crystal037 said:
Homework Statement:: The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations:: |a+b|=sqrt(a^2 +b^2 +2ab)
Your relevant equation is wrong, unless by ab, you mean the scalar product of vector a and vector b .

As far as a different reading of the problem (Yes, the given statement is ambiguous.):

Rather than one and the other referring to the two orthogonal vectors, perhaps they refer to the resultant and the difference vectors. Is this even possible?
 
SammyS said:
Is this even possible?
If two vectors ##\vec a## and ##\vec b## are orthogonal, then ##\vec a\cdot\vec b=0 \Rightarrow |\vec a + \vec b | = |\vec a - \vec b | ##
 
One comment about your notation: when the problem says "the magnitude of one is 2 times that of the other", it's not correct to write ##\vec b = 2 \vec a##. That would imply that the two vectors are parallel to each other and not orthogonal.
 
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SammyS said:
Try this instead.

If magnitude of one is ##\sqrt{2~} ## times that of the other, find the value of sec θ.
Yes then the answer comes as 3.