Resultant of two orthogonal vectors

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Homework Help Overview

The discussion revolves around finding the value of sec θ related to the resultant of two orthogonal vectors, where one vector's magnitude is stated to be twice that of the other. Participants are exploring the implications of this relationship and the interpretation of the problem statement.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the correctness of the book's answer and discussing potential misinterpretations of the problem statement. There are considerations of different interpretations regarding the vectors involved and their relationships.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning assumptions. Some have suggested alternative interpretations of the problem, while others have pointed out potential ambiguities in the wording. There is no explicit consensus on the correct interpretation yet.

Contextual Notes

There is mention of ambiguity in the problem statement, particularly regarding the relationship between the magnitudes of the vectors and their orientations. Participants are also noting the implications of the vectors being orthogonal.

Crystal037
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Homework Statement
The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations
|a+b|=sqrt(a^2 +b^2 +2ab)
IMG_20200327_160143.jpg

But the answer in my book is given that sec(theta) =3. Where am I going wrong?
 
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Crystal037 said:
Where am I going wrong?
I think nowhere. So the book answer must be a mistake.
You could come up with a better drawing, though. And a sign of the secant is minus if b = 2a.
 
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Maybe I am interpreting the question wrongly. I don't know if that is what the question is supposed to mean.
 
You worked out your interpretation. You think there is an alternative ?
 
Crystal037 said:
Homework Statement:: The resultant of two orthogonal vectors makes an angle θ with their difference. if magnitude of one is 2 times that of the other, find the value of sec θ.
Relevant Equations:: |a+b|=sqrt(a^2 +b^2 +2ab)
Your relevant equation is wrong, unless by ab, you mean the scalar product of vector a and vector b .

As far as a different reading of the problem (Yes, the given statement is ambiguous.):

Rather than one and the other referring to the two orthogonal vectors, perhaps they refer to the resultant and the difference vectors. Is this even possible?
 
SammyS said:
Is this even possible?
If two vectors ##\vec a## and ##\vec b## are orthogonal, then ##\vec a\cdot\vec b=0 \Rightarrow |\vec a + \vec b | = |\vec a - \vec b | ##
 
Stated differently, if the vectors are orthogonal, one can form a ##a\times2a## rectangle with them. One diagonal is the sum, the other is the difference and they have equal magnitudes. There are two angles between the diagonals to be considered, one being the supplementary of the other.
 
One comment about your notation: when the problem says "the magnitude of one is 2 times that of the other", it's not correct to write ##\vec b = 2 \vec a##. That would imply that the two vectors are parallel to each other and not orthogonal.
 
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Crystal037 said:
If magnitude of one is 2 times that of the other, find the value of sec θ.
Try this instead.

If magnitude of one is ##\sqrt{2~} ## times that of the other, find the value of sec θ.
 
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SammyS said:
Try this instead.

If magnitude of one is ##\sqrt{2~} ## times that of the other, find the value of sec θ.
Yes then the answer comes as 3.
 

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