Resultant velocities from 2D collision

Click For Summary

Homework Help Overview

The discussion revolves around calculating resultant velocities from a two-dimensional collision between two circles, where size is proportional to mass. The scenario assumes no elasticity or friction during the collision, and the circles have known x- and y-velocities. The original poster seeks clarification on how to approach this problem, particularly regarding the implications of elasticity and the mechanics of collision.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the angles of collision and momentum transfer, with the original poster attempting to understand the concept of elasticity and how it applies to their scenario. Questions arise about resolving velocities along the center-to-center line of the circles at the time of impact.

Discussion Status

Some participants have provided guidance on resolving velocities and applying expressions for final velocities, while others are exploring the implications of the assumptions made about elasticity and mass. The discussion is ongoing, with multiple interpretations being considered.

Contextual Notes

There is a mention of constraints regarding the definitions of elasticity and the nature of the collision, as well as the relationship between size and mass of the circles. The original poster expresses uncertainty about the mechanics involved and seeks further clarification.

Hurpadurp
Messages
2
Reaction score
0

Homework Statement


Suppose you have two 2D circles, where size ≈ mass, each of which is moving with known x- and y-velocities. The two collide, not necessarily head-on (one could broadside the other, etc). How do I calculate the resultant velocities, assuming no elasticity or friction?

Homework Equations


ρ = mv
m1v1 + m2v2 = m1v1` + m2v2`
Speed = Square root of (X-velocity^2 + Y-velocity^2)

The Attempt at a Solution


Each circle is moving in a particular angle (direction), and hits the other at a particular angle. If the difference between angles is 0, then the mower transfers all of its momentum to the other. If the difference is approaching 90 degrees, then the amount transferred is approaching 0.I apologize if this has already been answered; I couldn't find it.
Thanks!
 
Physics news on Phys.org
Hurpadurp said:

Homework Statement


Suppose you have two 2D circles, where size ≈ mass, each of which is moving with known x- and y-velocities. The two collide, not necessarily head-on (one could broadside the other, etc). How do I calculate the resultant velocities, assuming no elasticity or friction?

Homework Equations


ρ = mv
m1v1 + m2v2 = m1v1` + m2v2`
Speed = Square root of (X-velocity^2 + Y-velocity^2)

The Attempt at a Solution


Each circle is moving in a particular angle (direction), and hits the other at a particular angle. If the difference between angles is 0, then the mower transfers all of its momentum to the other. If the difference is approaching 90 degrees, then the amount transferred is approaching 0.


I apologize if this has already been answered; I couldn't find it.
Thanks!

Hello Hurpadurp,
What do you mean by size ≈ mass?And what is the constraint "no elasticity"?Do you mean that the balls are identical and the collision is assumed to be elastic without any non conservative forces? If yes try to resolve the velocities along the center to center line of spheres at the time of impact.You will be done.
regards
Yukoel
 
Yukoel,

Here's a little more information on why I'm asking this:
I'm making a program in which objects, represented by circles, are moving around on the screen. When they hit each other, a collision function is called - the size of the circle is the same as its mass; e.g. circles of radius 70 units have half the mass of circles of radius 140 units. For ease of use, let's say the units are meters, and convert nicely to kilograms; the speeds are in m/s.
I'm unfamiliar with the concept of elasticity (my recent college courses just dealt with head-on collisions with either negligible or a specific amount of friction). In here, there are no non-conservative forces.

I'm sorry, but what do you mean by resolving "the velocities along the center to center line of spheres at the time of impact?"

Thanks,
Hurpadurp

Edit: A little more information: I checked http://en.wikipedia.org/wiki/Elastic_collision#Two-_and_three-dimensional but I don't quite understand if it's explaining the situation for the second particle being at rest, or more generally.
 
Last edited:
Hurpadurp said:
Yukoel,

Here's a little more information on why I'm asking this:
I'm making a program in which objects, represented by circles, are moving around on the screen. When they hit each other, a collision function is called - the size of the circle is the same as its mass; e.g. circles of radius 70 units have half the mass of circles of radius 140 units. For ease of use, let's say the units are meters, and convert nicely to kilograms; the speeds are in m/s.
I'm unfamiliar with the concept of elasticity (my recent college courses just dealt with head-on collisions with either negligible or a specific amount of friction). In here, there are no non-conservative forces.

I'm sorry, but what do you mean by resolving "the velocities along the center to center line of spheres at the time of impact?"

Thanks,
Hurpadurp

Edit: A little more information: I checked http://en.wikipedia.org/wiki/Elastic_collision#Two-_and_three-dimensional but I don't quite understand if it's explaining the situation for the second particle being at rest, or more generally.
Hello Hurpaderp,
Um I made this image here at http://img823.imageshack.us/img823/4985/f5461f6608dd48fdb74f6a2.png (I am bad at paint and photoshop so sorry :( )
I think it is kinda what your situation demands.The center to center line is the red line(in the picture).Resolve velocities along this line and apply expressions for final velocities on them like two masses colliding with given initial velocities.The tangential component(the component perpendicular to the red line) remains untouched.The wiki link shows a stationary equal mass being acted upon by the collision.This is why the final trajectories of both are perpendicular.
Hoping this helps.
regards
Yukoel
 
Last edited by a moderator:

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K