Revenue Question with Linear Function HELP

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Homework Help Overview

The discussion revolves around a revenue problem involving a linear function, specifically focusing on expressing revenue as a function of price, sketching the corresponding graph, and determining the price for maximum revenue based on a given demand function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to express revenue solely in terms of price, with initial attempts to rewrite the revenue equation using the demand function. Questions arise about graphing the function and identifying key points such as intercepts and the vertex.

Discussion Status

Participants have made progress in rewriting the revenue function and discussing its graph. Some have calculated intercepts and the vertex, while others are questioning the clarity of variable representation. There is an ongoing exploration of how to find the maximum revenue and the corresponding price.

Contextual Notes

Participants are navigating the constraints of the problem, including the need to express revenue in terms of price and the implications of using calculus for optimization. There is some confusion regarding variable notation and its impact on understanding the problem.

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Revenue Question with Linear Function **HELP**

Homework Statement


(a) Express revenue (R=pq) as a function solely of p
(b) Sketch the graph of R as a function of p. Clearly label the x-intercept(s), y-intercept(s), and vertex (if there is one)
(c) At what price should you sell the Pen Tablets to get the largest revenue? What is the largest possible monthly revenue?

Homework Equations


q = -0.5p + 140 <-- demand function for Pen Tablets
q --> number of Pen Tablets that can be sold/month
p --> price ($) per Pen Tablet

The Attempt at a Solution


Once again I need a little help getting started on part (a), how can I make this be a function of only p
:eek:
PLEASE HELP get my STARTED on this!
 
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a) If R = p*q and q = -0.5p + 140, can you rewrite R solely in terms of p?
 


Mark44 said:
a) If R = p*q and q = -0.5p + 140, can you rewrite R solely in terms of p?

Mark:!) Yes I can lol:
R = p(-0.5p + 140)
R = -0.5p2 + 140p
 


Well, good!
What does the graph look like (part b)? Be sure to label the vertex, since that figures into part c.
 


R = -0.5p2 + 140p --> y = -0.5x2 + 140x
Use the Quadratic Formula to find the two values of x:
x=-140 +/- [tex]\sqrt{140^2 - 4(-0.5)(0)}[/tex] /2(-0.5)
x = 280 OR 0

when x = 280
y = -0.5(280)2 + 140(280)
y = -39200 + 39200
y = 0
when x = 0
y = -0.5(0)2 + 140(0)
y = 0

--> therefore the two intercepts are (280,0) and (0,0)
Vertex:
h=-b/2a
h=-140/2(-0.5)
h=140

y=-0.5(140)2 + 140(140)
y=9800

--> therefore the vertex is (140,9800)

now, for part (c)which one is which:blushing:
 


Well how do you find the largest anything in calculus?
 


NoMoreExams said:
Well how do you find the largest anything in calculus?

Uuhm...I have no Idea:confused:
dont I use the vertex to find this?
so --> the vertex is (140,9800)
is the 140 the p ? cos if it is I would sub p into the equation q = -0.5p + 140
so that q = -0.5(140) + 140
then q = 70
THEN
R = pq = 70*140 = 9800 ---> lol you I knew the R was the y part of the vertex...
anyways if NOT I just did a whole lot of typing for nothing :rolleyes:
 


Why did you change to x and y? Now you don't know which one is which. The variable p (unit price) and R (total revenue) would be more helpful to keep things straight.

And here's the question for c):
At what price should you sell the Pen Tablets to get the largest revenue? What is the largest possible monthly revenue?
 


I know Mark lol...I have no Idea why I changed it..it seemed easier at the time:redface:
sooo the fact that your not responding to my calculation means that they are...wrong?!
I drew the graph and the y-axis is the R and the x-axis is the p
so to answer (c):
I should sell the Pen Tablets at $140 to get the largest revenue AND The largest possible monthly revenue is $9800!
Correct?!
 
  • #10


Looks good.
 
  • #11


Woohoo!:!)
 

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