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If it is thermodynamically favored for a reaction to occur forward and reverse, does that mean that the standard enthalpy of the reaction is close to 0?
The discussion centers on the relationship between standard enthalpy and thermodynamic favorability of reactions. It concludes that if both forward and reverse reactions are thermodynamically favored, the standard enthalpy change is indeed close to 0. Additionally, when the rates of the forward and reverse reactions are comparable, the standard Gibbs Free Energy change approaches 0, indicating equilibrium conditions.
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If the forward and reverse reaction rates are comparable, you will find the the standard Gibbs Free Energy change for the reaction is close to 0.dissolver said:If it is thermodynamically favored for a reaction to occur forward and reverse, does that mean that the standard enthalpy of the reaction is close to 0?