Reverse the order of integration?
Original has it in the form of dy dx, 0<=x<=ln6, 1<=y<=e^x.
I made it dx dy, with 1<=x<=e^y, 0<=y<=ln6
Is this right?
Wow, you waited 12 whole minutes before bumping? That's a good way to get banned from this forum!
Draw a graph. x ranges between 0 and ln(6) so draw two vertical lines there. For each x[/itex], y ranges from 1 to [itex]y= e^x[/itex] do draw the horizontal line y= 1 and the [itex]y= e^x[/itex]. Notice that [itex]e^0= 1[/itex] so that forms something that looks like a kind of "right triangle" with a curved hypotenuse.
Now, what are the lowest and highest value of y in that "triangle"? Saying that x< ln 6 does NOT mean y< ln 6. y is not x!
Imagine a horizontal line at some y-value. x ranges from the left end of that line to the right end. What are those values?
[itex]y= e^x[/itex] does NOT give [itex]x= e^y[/itex]! Solve [itex]y= e^x[/itex] for x.