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Revolutions of a tire and angle in radians thru warranty

  1. Feb 29, 2012 #1
    1. The problem statement, all variables and given/known data
    The tires on a new car have a radius of .275 meters and are warranted for 75,000km

    a)what is the angle in radians that one of these tires will rotate thru in the warranty period?
    b) how many revolutions does this make?


    2. Relevant equations
    1rev = 2pi radians
    circumference = 2pi*r


    3. The attempt at a solution
    circumference = (2pi)(.275m) = 1.727m
    b) 75m/.001727= 43427.9
    a) 43427 *2pi = 272865
     
  2. jcsd
  3. Feb 29, 2012 #2

    Pengwuino

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    Gold Member

    Your calculation for b) is wrong. You should find the number of revolutions as [itex]{{75,000,000m}\over{1.727 {{m}\over{turn}}}}[/itex]
     
  4. Feb 29, 2012 #3
    43,427,909.66 revolutions.
    to find the angle do i multiply this by 2pi?
     
  5. Feb 29, 2012 #4

    Pengwuino

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    Gold Member

    Yes.
     
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