# Revs per min from metres per second

1. ### Taryn

66
okay so here is the problem and here is wat I did!
I am just tryin to study up for exams now... and this is one of the problems!

A sample of blood is placed in a centrifuge of radius 17.5 cm. The mass of a red corpuscle is 3.00×10-16 kg, and the magnitude of the force required to make it settle out of the plasma is 4.08×10-11 N. At how many revolutions per second should the centrifuge be operated?

Basically wat I did is found the velocity in metres per second first which I find is 154m/s which I found by usin F=(mv^2)/r
But here is the simple problem that I am confused about... how do I change this to revs/sec. Is it somethin to do with C=2PIr, thats all I can think of!
Thanks for your help!

2. ### Hootenanny

9,681
Staff Emeritus
You could do it that way, however it is easier to remember that if we resolve newton's second law radially we achieve;

$$F = m\alpha$$

Where alpha is centripetal acceleration and $\alpha = r\omega^2$ where omega is angular velocity (rads/s). Thus;

$$\fbox{F = mr\omega^2}$$

You method is completely valid, but is a bit long winded . You can convert radians per second into revolutions per second by dividing by $2\pi$.

Last edited: Jun 6, 2006
3. ### Taryn

66
okay I did that and now I am so far off... I did 123686.127rev/sec.
so wat I did was w^2=f/mr
but then I got that in rads per second =7.77E5 which is bigger then I expected.
So I then divided by 2*PI... then it was wrong... the answer is meant to be 140.3

4. ### Hootenanny

9,681
Staff Emeritus
You forgot to square root the 7.77x105. If you square root that value then divide by $2\pi$ you sould obtain the correct answer.

5. ### Taryn

66
thanks a lot I appreciate it, I thought I did sqaure root the answer but now I got the right answer.! ;P

6. ### Hootenanny

9,681
Staff Emeritus
No problem

7. ### Andrew Mason

6,805
I am sure you meant to say that the quantity $r\omega^2 = v^2/r$ is the centripetal acceleration not angular acceleration.

AM

8. ### Hootenanny

9,681
Staff Emeritus
Thank-you andrew, duly corrected.

Know someone interested in this topic? Share a link to this question via email, Google+, Twitter, or Facebook