Rewriting SHM equation from a function of sin(wt) and cos(wt) to just cos(wt-∅)

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SUMMARY

The discussion focuses on rewriting the equation of motion x(t) = 2cos(wt) - 2sin(wt) into the form x(t) = C cos(wt-∅). The constant C is calculated as √8, derived from the magnitudes of the sine and cosine components. The angle ∅ is determined using the formula ∅ = arctan(b/a), where b and a correspond to the coefficients of the sine and cosine terms, respectively. This transformation is essential for simplifying the analysis of harmonic motion.

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Homework Statement


Rewrite the equation of motion x(t) = 2cos(wt) - 2sin(wt) in the form x(t) = C cos(wt-∅)


Homework Equations




The Attempt at a Solution


I am able to work out the constant C as it is just the magnitude of the sin and cos function,

C = (2^2 + 2^2)^1/2 = √8

However I am unable to find ∅, can anyone point me in the direction of how to do this?

Many thanks

James
 
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Hint:

General equation of motion is: x=Asin wt+Bcos wt. If started from position x0 with velocity v0

x = v0/w sin wt + x0cos wt

Make substitution:

x0 = X sin theta
v0/w = X cos theta
 


LawrenceC said:
Hint:

General equation of motion is: x=Asin wt+Bcos wt. If started from position x0 with velocity v0

x = v0/w sin wt + x0cos wt

Make substitution:

x0 = X sin theta
v0/w = X cos theta

Thanks that was all I needed!

Essentially ∅ = arctan(b/a)

Thanks for the help!
 

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