Riemann Stieltjes Integral help

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SUMMARY

The discussion focuses on calculating the Riemann-Stieltjes integral of the function f defined as f(x) = x for 0 ≤ x ≤ 1 and f(x) = 1 for x > 1, with respect to the function α defined as α(x) = x² for 0 ≤ x ≤ 1 and α(x) = 1 for x > 1. The integral is evaluated from 0 to 23, simplifying to an ordinary Riemann integral due to the piecewise nature of both functions. The differential dα is determined as dα = 2xdx for 0 ≤ x ≤ 1 and dα = 0 for x > 1, leading to the conclusion that the integral can be computed directly using standard integration techniques.

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prudens2010
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Code:
Let f = 

x, for 0<=x<=1
1, for 1<x

alpha =

x^2, for 0<=x<=1
1, for 1<x

Find Integral (f) d(alpha) -- from 0 to 23

pls help!
 
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prudens2010 said:
Code:
Let f = 

x, for 0<=x<=1
1, for 1<x

alpha =

x^2, for 0<=x<=1
1, for 1<x

Find Integral (f) d(alpha) -- from 0 to 23

pls help!

Use the definition of the R-S integral. The answer should pop right out unless I'm missing something. Where does the problem lose you?
 
This case easily translates into an ordinary Riemann integral.
dα = 2xdx, 0≤x≤1
dα = 0, x>1
 

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