Right-Hand Rule: Finding Induced Direction in a One Loop Wire on the Page

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A one-loop wire lying on a page with a magnetic field pointing into the page experiences an induced current due to the increasing magnetic field strength. The induced current flows counterclockwise to oppose the increase in magnetic flux, as determined by the right-hand rule. When the magnetic field is increasing, the thumb points in the direction of the induced field, and the fingers curl in the direction of the induced current. The discussion also touches on torque in a rectangular wire loop with a clockwise current in a magnetic field, emphasizing the relationship between current direction and torque direction. Understanding these principles is crucial for solving related physics problems effectively.
Noreturn
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1. The problem statement, all variables, and given/known data
A one loop wire is lying on the page with a magnetic field pointing into the page. The magnetic field strength is increasing with time, the induced current direction in the loop is:

Assume magnetic field is pointing into the page and is increasing with time. If a wire loop is laying on the page perpendicular to the magnetic field the induced current will flow clockwise. T/F

Homework Equations



Right-Hand Rule

The Attempt at a Solution


So I know how to use the right-hand rule when I am using the 3 fingers w/ the 3 forces where:
middle: magnetic field
index: velocity
thumb: force field

I get confused when it starts saying it's lying on the page parallel to the right side then gives only one force..I know the other right-hand rule where we can have thumb be the direction of current the curling of fingers is the flow of the force. Then induced would be the opposite direction correct?

Thanks for any help, know it's kinda hard to explain over text.
 
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Since the induced current will be in a direction as to oppose the change of flux, if you point your thumb in the direction of the induced field, your fingers will curl in the direction of the induced current.

In this problem, the field is pointing into the page and the flux through the loop is increasing. The induced field will want to oppose this increase this in flux and so which way do you think you should point your thumb? Which way do your fingers curl when you do this?
 
RedDelicious said:
Since the induced current will be in a direction as to oppose the change of flux, if you point your thumb in the direction of the induced field, your fingers will curl in the direction of the induced current.

In this problem, the field is pointing into the page and the flux through the loop is increasing. The induced field will want to oppose this increase this in flux and so which way do you think you should point your thumb? Which way do your fingers curl when you do this?

So on the second one, we can say it's false because if we point thumb into the page the natural flow is clockwise so induced would be counterclockwise. The first one I know the answer is to the right but do know why.
 
Noreturn said:
So on the second one, we can say it's false because if we point thumb into the page the natural flow is clockwise so induced would be counterclockwise. The first one I know the answer is to the right but do know why.

Yes.

I think you may have miscopied the other question in your initial post. What exactly is the question?
 
Oh I did, didn't even notice:
A rectangular wire loop is lying on the page with one of its edges parallel to the right side of the page. A clockwise current of 1 A is flowing in the wire loop. A magnetic field lies in the page pointing from left towards right side of the page, the torque on the current loop is a) points to the top of the page, b) to the left, c) to the bottom of the page, or d) into the page
 
Where the current is parallel to the magnetic field, what do you expect the torque to be (in general)?
How about when it's perpendicular?

Look up "magnetic dipole moment" if you have no idea.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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