fluidistic
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I understand everything if I assume that Vcm = Wcm * a. Could you explain a bit more how do you get it?darkxponent said:okay
NOW let's visualise:
fisrt i forgot 'Wc' . Just forget that it exists in the question.
i only know Wcm and Vcm:
NOW according to pure rolling Vcm = Wcm * a;
now the only twist is that this cyllinder is rolling not on a plane but in cyllindrical surface
We Find time period(Tc) of the cyllinder = 2*pi*(R-a)/Vcm
THIS GIVES Wc as::
Wc = 2*pi/Tc
= Vcm/(R-a)
=Wcm *a/(R-a)
You considered a cylinder of radius a rolling over a plane (with rolling and not slipping?)? In those case I don't understand the meaning of \omega _{CM}. I mean the cylinder rotates around an axis that passes through the center of mass over a plane. Since the center of mass does not rotate, omega of center of mass is worth 0... What am I misunderstanding?