Rings Generated by Elements - Lovett, Example 5.2.1 .... ....

  • Context: Undergrad 
  • Thread starter Thread starter Math Amateur
  • Start date Start date
  • Tags Tags
    Elements Example Rings
Click For Summary
SUMMARY

The discussion centers on Example 5.2.1 from Stephen Lovett's "Abstract Algebra: Structures and Applications," specifically regarding the ring generated by the elements of the form ##\{ \frac{k}{ 2^n} \ | \ k,n \in \mathbb{Z} \}##. It is established that this set is a subring of ##\mathbb{Q}## and is precisely the ring ##\mathbb{Z} [ \frac{1}{2} ]##, as it contains both ##\mathbb{Z}## and ##\frac{1}{2}##. Participants confirm that ##\mathbb{Z} [ \frac{1}{2} ]## is indeed the smallest subring of ##\mathbb{Q}## containing these elements, demonstrating closure under ring operations. The discussion clarifies that Lovett's proof effectively shows the necessary inclusions and properties of the ring.

PREREQUISITES
  • Understanding of ring theory and subrings
  • Familiarity with the notation and properties of rational numbers (##\mathbb{Q}##)
  • Knowledge of integer sets (##\mathbb{Z}##) and their operations
  • Basic concepts of ring extensions in abstract algebra
NEXT STEPS
  • Study the properties of subrings in abstract algebra
  • Learn about ring extensions and their implications in algebraic structures
  • Explore the concept of smallest subrings generated by sets
  • Investigate other examples of rings generated by elements in Lovett's text
USEFUL FOR

Students and educators in abstract algebra, particularly those studying ring theory and its applications, as well as anyone seeking to deepen their understanding of the structure of rings generated by specific elements.

Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
I am reading Stephen Lovett's book, "Abstract Algebra: Structures and Applications" and am currently focused on Chapter 5 ...

I need some help with Example 5.2.1 in Section 5.2: Rings Generated by Elements ...
?temp_hash=2e165cf6b1bf5270d1f5c27106307918.png

In the Introduction to Section 5.2.1 (see text above) Lovett writes:

" ... ... R[S] denotes the smallest (by inclusion) subring of ##A## that contains both ##R## and ##S## ... ... "Then, a bit later, in Example 5.2.1 concerning the ring ##\mathbb{Z} [ \frac{1}{2} ]## Lovett writes:" ... ... It is not hard to show that the set##\{ \frac{k}{ 2^n} \ | \ k.n \in \mathbb{Z} \}##is a subring of ##\mathbb{Q}##. Hence, this set is precisely the ring ##\mathbb{Z} [ \frac{1}{2} ]## ... ... ... "BUT ...

How has Lovett actually shown that the set ##\{ \frac{k}{ 2^n} \ | \ k.n \in \mathbb{Z} \}## as a subring of \mathbb{Q} is actually (precisely in Lovett's words) the ring ##\mathbb{Z} [ \frac{1}{2} ]## ... ...

... ... according to his introduction which I quoted Lovett says that the ring ##\mathbb{Z} [ \frac{1}{2} ]## is the smallest (by inclusion) subring of ##\mathbb{Q}## that contains ##\mathbb{Z}## and ##\frac{1}{2}## ... ...Can someone please explain to me exactly how Lovett has demonstrated this ... ...

... and ... if Lovett has not clearly proved this can someone please demonstrate a proof ...Just one further clarification ... is Lovett here dealing with ring extensions ... ... ?

Hope someone can help ...

Peter
 

Attachments

  • Lovett - Example 5.2.1.png
    Lovett - Example 5.2.1.png
    48 KB · Views: 843
Last edited by a moderator:
Physics news on Phys.org
1) {k/2n | k,n∈ℤ} is a subring that contains ℤ and 1/2. Therefore, ℤ[1/2] ⊆ {k/2n | k,n∈ℤ}.
2) Pick any element k/2n, k,n∈ℤ. For ℤ[1/2] to be a closed ring under an obvious series of operations, it must contain that element. Therefore {k/2n | k,n∈ℤ} ⊆ ℤ[1/2].
 
  • Like
Likes   Reactions: Math Amateur
Thanks FactChecker ... I think I now follow ...

Appreciate your help ...

Peter
 
  • Like
Likes   Reactions: FactChecker

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K