RLC Circuit Help: Find Max Source Voltage & Power Factor

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SUMMARY

The discussion focuses on calculating the maximum source voltage and power factor for an RLC circuit comprising a 210-ohm resistor, a 2.9µF capacitor, and a 390mH inductor connected to a 100Hz AC power supply with a peak-to-peak voltage of 40.0V. The maximum source voltage is determined to be 20V, which is half of the peak-to-peak voltage. The power factor is computed using the cosine of the phase angle, which is found to be -57 degrees, indicating the phase relationship between voltage and current in the circuit.

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Homework Statement


A 210 ohm resistor in series with 2.9uF capacitor and 390mH inductor are put across a 100Hz ac power supply with a peak-to-peak terminal voltage of 40.0V.
a) What 's the maximum source voltage?
b) Compute the power factor

Homework Equations


tantheta= (Vl-Vc)/Vr
cos(phase angle)??

The Attempt at a Solution



a) 20V = answer...I put 40V..why is it 20V??

b) how do I compute the power factor? what does it mean??
 
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The peak-to-peak voltage is, as the name implies, the difference between the highest and lowest possible voltages. The amplitude of the voltage is (by definition) half of this distance, thus 20 V.

For b, if you don't know what the power factor is, you should really consult your textbook or a reliable website. It's a crucial concept that can't be explained in a few lines.
 
for the power factor, I did cos(-57) and got the right answer...
but why is it -57?? which is the phase angle??
 

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