Rlc circuit with ac current source

Click For Summary

Homework Help Overview

The problem involves an RLC circuit with an AC current source of 1 ∠0° A and an angular frequency of 1 rad/s. The circuit includes a capacitor, inductor, and resistor arranged in a specific configuration, and the goal is to find the voltage across the capacitor.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between impedances and resistors, questioning whether they can be treated similarly in calculations. There are attempts to apply the current divider rule and find the net impedance of the circuit. Some participants inquire about the concept of complex impedance.

Discussion Status

The discussion is ongoing, with various approaches being explored. Participants are sharing their understanding of impedance and its application in the circuit, but no consensus has been reached on the method to solve for the voltage across the capacitor.

Contextual Notes

Participants are navigating the complexities of series and parallel configurations in RLC circuits, and there may be uncertainties regarding the application of formulas and the concept of complex impedance.

Mirthlinc
Messages
2
Reaction score
0

Homework Statement


An AC current source, 1 ∠0° A, with angular frequency 1 rad/s is to be applied to the input
terminals of the circuit. Circuit is RLC, the current source is in parallel with a 1F capacitor which is in parallel with a 1H inductor which is in series with a 1Ω resistor. I need to find the Voltage across the capacitor.


Homework Equations



Xc = 1/ωC

Vc = Xc * I



The Attempt at a Solution



I know that the voltage into the circuit is the same as the voltage across the capacitor since they are in parallel. This is a current divider problem so I need to find the current across the capacitor to solve for the Vc. I know I need to use the impedences to solve for voltage using Vc = Xc * Ic, but I cannot recall how to do this for a series/parallel RLC circuit.
 
Physics news on Phys.org
Is it that impedences act the same as resistors? In that case I just add the series elements and then use the current divider rule to find the current across the capacitor, but I don't know if that is right.
 
First find the net impedence of the circuit.
 
Have you been introduced to the concept of complex imedance?
 
Step 1. The impedance of the capacitor = 1/(wC) ∠-90°

Step 2. Impedance of the inductor + impedance of resistor = [PLAIN][PLAIN]https://www.physicsforums.com/images/icons/icon5.gif ∠[PLAIN][PLAIN]https://www.physicsforums.com/images/icons/icon5.gif  + [PLAIN][PLAIN]https://www.physicsforums.com/images/icons/icon5.gif ∠[PLAIN][PLAIN]https://www.physicsforums.com/images/icons/icon5.gif
 
Last edited by a moderator:

Similar threads

  • · Replies 15 ·
Replies
15
Views
6K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K