My apologies HallsofIvy. I've been experiencing ISP issues and getting bumped repeatedly, so I typed up what I thought may have been the "quick and easy" explanation, posted it, and didn't have a chance to thoroughly recheck it before I got bumped again. It took me the last 20 minutes or so just to get reconnected.
It will depend on each specific situation. One g of acceleration is about 9.8 meters per second per second. 9.8[tex]m/s^2[/tex]
So at the point in the launch the rockets speed is changing by 9.8[tex]m/s^2[/tex] the craft is experiencing one g over and above the acceleration due to gravity.
? G force has nothing to do with velocity- it depends on acceleration. Was that just a repeated misprint? (Referring to Gnosis' post.) The formula should be (a/g)+ 1, not (v/g)+ 1. That is, you feel your normal weight due to gravity plus an additional "weight" due to the force causing the acceleration.