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## Homework Statement

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http://imgur.com/a/Ssolz

## Homework Equations

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Elastic Collision so $$ mgh = \frac{1}{2}mv_i^2 = \frac{1}{2}mv_f^2 + \frac{1}{2}I\omega^2 $$

$$ F=ma $$

## The Attempt at a Solution

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So the problem is similar to this one which allows me to work out the normal force at the point of contact.

I have

$$ma = mg - N$$

$$dN = I\dot{\omega}$$

$$\dot{\omega} = \frac{a}{d}$$

So

$$\frac{dN}{I} = \frac{mg-N}{md}$$

But to be honest I don't know if this is even useful as there is no guarantee the rod sits on the edge after the collision. Any help would be appreciated.