Rod pivoting at top: impulse needed for 360° rotation and oscillation period

[Andreas]

A homogene rod with length "l" is placed vertically, and a nail is stabbed on the top of the rod (now the rod has an axis). And then an impulse is given on the rod with the separation between the impulse given to the rod's axis is "d". Earth gravitational acc is represented as g, the mass of the rod is m. Now, calculate the minimum value of d to make the rod rotate 360°.

Now if the condition above is complete, and the rod make a harmonic movement (oscillation) what is the period?

And what is the length of a mathematical pendulum should be to make the same period with the oscillating rod?

 

[kuruman]

The questions about the pendulum and oscillations can be answered with a little bit of internet research on key word "physical pendulum". The question about the minimum value of $d$ given an impulse $J$ can be answered by using angular momentum conservation to find the initial angular speed about the pivot and then mechanical energy conservation to say that all the initial kinetic energy is converted to potential energy when the stick is vertical with the center of mass at distance $l/2$ above the nail.
$$J d=\frac{1}{3}ml^2\omega~\rightarrow~\omega=\frac{3Jd}{ml^2}$$
$$mgl<\frac{1}{2}ml^2\omega^2=\frac{1}{2}\times\frac{1}{3}ml^2\left(\frac{3Jd}{ml^2}\right)^2~\rightarrow~d_{min}=\frac{m}{J}\sqrt{\frac{2gL^3}{3}}.$$