Roll resistance calculations error?

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SUMMARY

The forum discussion centers on calculating roll resistance in vehicle suspension using the formula (SF/(WmF/SmF)^2) x TF^2 [ x ] 2 x ∏ / 180 = ArF. The user, Jason, seeks clarification on the correct placement of the multiplication symbol within the formula and the interpretation of the units "in.lbs per degree." The example provided indicates a calculation error, as the expected result does not match the output from the formula. The discussion highlights the importance of understanding both the formula's structure and the units involved in roll resistance calculations.

PREREQUISITES
  • Understanding of vehicle dynamics and weight transfer concepts
  • Familiarity with suspension geometry and spring rates
  • Basic knowledge of mathematical operations and unit conversions
  • Experience with engineering calculations related to automotive performance
NEXT STEPS
  • Research "Vehicle Dynamics and Weight Transfer" for foundational knowledge
  • Study "Spring Rate Calculations in Suspension Systems" for practical applications
  • Learn about "Unit Conversion in Engineering" to clarify units like in.lbs
  • Explore "Advanced Suspension Geometry" for deeper insights into roll resistance
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Automotive engineers, suspension designers, and students studying vehicle dynamics will benefit from this discussion, particularly those focused on performance tuning and suspension optimization.

Jas1159
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Hi,

I am trying to calculate weight transfer from the front to rear of a vehicle and have already calculated the total sprung weight to be transfered.

I now need to calculate the Roll resistance generated by the springs using the following forumula and this is where the error occurs.

(SF/(WmF/SmF)^2) x TF^2 [ x ] 2 x ∏ / 180 = ArF

In laymens terms

SF = Front Spring Rate
WmF=Front Wheel Movement
SmF=Relative Front Spring Movement
TF = Front Track
ArF = Roll Resistance of Front Springs

Now i can't figure out if the x i placed in brackets [ ] is supposed to be / (x or /)?

The example is as follows;

(175/(1.00/0.75)^2)xTF^2x2xPi/180 = 2889.77 in.lbs per degree (roll resistance of front springs)

you will notice that the formula does not equate to the answer and to obtain the answer i must devide... which present me with a problem as my understanding of this particular aspect is clouded by my understanding of the units...

I realize this is probably a 'suck eggs' moment but can somebody explain in practical terms what is meant by in.lbs per degree... the amount of in.lbs per degree of roll but in.lbs is both a distance and a weight...

Any help with either or both of the above problems will be much appreciated.

Regards
Jason
 
Last edited:
Engineering news on Phys.org
hello and Welcome
suggest you read Race car suspension Class
on t his mech eng forum posted Jul29-09

page two has calc for spring ratesmerry Christmas
rm
 

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