Roller Coaster Problem with KE and PE

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SUMMARY

The discussion focuses on solving the Roller Coaster Problem using the principles of kinetic energy (KE) and potential energy (PE). The user proposes the equation (PEb + KEb = KEa + PEa) to analyze energy transformations between points A, B, and C. They correctly identify that the work done by gravity (W = mgΔh) relates to the changes in kinetic and potential energy. The conversation emphasizes the importance of calculating potential energy at various points to fully understand the energy dynamics of the roller coaster system.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PE) concepts
  • Familiarity with the work-energy principle in physics
  • Basic knowledge of gravitational potential energy calculations
  • Ability to manipulate algebraic equations for problem-solving
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn how to apply conservation of energy principles in mechanical systems
  • Explore examples of potential energy calculations at different heights
  • Investigate the relationship between velocity and energy in roller coaster dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of energy transformations in real-world scenarios.

chris61986
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Homework Statement



https://dl.dropbox.com/u/92857534/physicsproblem.png

Note: Solving for part D and E

Homework Equations



Unsure. language in the problem seems ambiguous.
Perhaps (KE + PE)b = (KE + PE)a

The Attempt at a Solution



So I think it's done this way.

From A to B and B to C, the equation would look this way:
PEb + KEb = KEa + PEa
PEa = 0, move KEb to right side, left with:
PEb = KEa - KEb
so WGH = 1/2mv'^2 - 1/2mv^2

Am I going the right way about this? If so, where do I go from here when I don't know both velocities?
Also, for parts A, B, and C, it's simply W = mgΔh, correct? I'm not used to things being easy :P
 
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Work energy rule says that the increase in kinetic energy of a body is equal to work done on it.
 
Do you think you could be a little less cryptic?
 
Work done by gravity is equal to the increase in kinetic energy of the car. The same is the loss in potential energy. W = mgΔh is correct.
In second part I think potential energy is to be calculated at different points.
 

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